Plasmolysis can be defined as the process where cells lose
water concentration in a hypertonic solution and this process leads to contraction or shrinkage of the pant cell
protoplasm. However, water leaves the cell due to hyperosmotic solution
because it contains solutes such as sorbitol, sucrose and mannitol.
Answer:
Please find the complete table attached as an image
Explanation:
This task is describing the processes of transcription and translation, which are the two processes involved in gene expression. The DNA of a human and cow is given in the table of the attached image and we're asked to transcribe into a complementary RNA, and subsequently translate into an amino acid using the CODON table (genetic code).
- Transcription is the process whereby DNA is used as a template for the synthesis of RNA based on complementary base pairing i.e. A-U, G-C, T-A etc.
- Translation is the process whereby RNA transcript is used to synthesize an amino acid sequence. The mRNA is read in a group of three nucleotides called CODON, where each of this codon specifies an amino acid.
The table has been completed and attached below. Note that in the amino acids row;
GLY means Glycine
ILE means Isoleucine
VAL means Valine
GLN means Glutamine
CYS means Cysteine
THR means Threonine
SER means Serine
PHE means Phenylalanine
ALA means Alanine
LEU means Leucine
The formation oil, that is, sweet crude, is typically that accumulate on the seafloor and "kitchen" of the geothermal gradient to be altered in petroleum products.while <span>Most of the </span>coal<span> we use now was </span>formed<span> about 300 million years ago, when much of the </span>earth<span> was covered by steamy swamps.
hope that helped</span>
Answer:
An autosomal dominant gene is one that occurs on an autosomal (non-sex determining) chromosome. As it is dominant, the phenotype it gives will be expressed even if the gene is heterozygous.
The chances of an autosomal dominant disorder being inherited are 50% if one parent is heterozygous (NL) for the mutant gene and the other is homozygous for the normal (NN), or 'wild-type', gene. This is because the offspring will always inherit a normal gene from the parent carrying the wild-type genes, and will have a 50% chance of inheriting the mutant gene from the other parent. If the mutant gene is inherited, the offspring will be heterozygous for the mutant gene, and will suffer from the disorder. If the parent with the disorder is homozygous for the gene, the offspring produced from mating with an unaffected parent will always have the disorder.
Explanation:
