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Yanka [14]
2 years ago
6

Patients in a hospital are classified as surgical or medical. A record is kept of the number of times patients require nursing s

ervice during the night and whether or not these patients are on Medicare. The data are presented here: Patient Category Medicare Surgical Medical Yes 46 52 No 36 43 Test the hypothesis (using ) that calls by surgical-medical patients are independent of whether the patients are receiving Medicare. Find to 2 decimal places the P-value for this test. The evidence Choose the answer from the menu in accordance to the question statement sufficient to claim that surgical-medical patients and Medicare status are dependent.
Mathematics
1 answer:
GREYUIT [131]2 years ago
5 0

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Given:

N= 177\\\\a=46\\\\b=52\\\\c=36\\\\d=43

\to \chi _{1}^{2}=\frac{N(ad-bc)^{2}}{(a+c)(b+d)(a+b)(c+d)}

         =\frac{177((46\times 43)-(52 \times 36))^{2}}{(98)(79)(82)(95)}\\\\=\frac{177((1978)-(1872))^{2}}{60310180}\\\\=\frac{177(106)^{2}}{60310180}\\\\=\frac{177(11236)}{60310180}\\\\=\frac{1988772}{60310180}\\\\= 0.032976

P-value= CHIDIST(0.032976,1) = 0.86.

thus, the surgical-medical patients and Medicare are dependent.

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Plz help and explain
Westkost [7]

Answer:  B

<u>Step-by-step explanation:</u>

In order to get the best representative sample, you should choose the widest range of students, which is from a random sample of all students.

(A) Choosing from only the 6th graders, eliminates the choices the other grade-level students would choose.

(C) Choosing only from students who participate in after-school activities, eliminates the choices the other students would choose.

(D) Chhosing only from students not participating in the fundraiser is silly since you want to know what the students participating in the fundraiser would choose.

The only possible option is B - students from all grades, regardless of whether or not they participate in after-school activities.

5 0
3 years ago
Find the sum of the first 90 terms of the sequence -4,-1,2,5,8
telo118 [61]

Answer:

1655

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence

d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3

This indicates the sequence is arithmetic with sum to n terms

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

Here a₁ = - 4, d = 3 and n = 90, thus

S_{90} = \frac{90}{2} [ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655

4 0
3 years ago
The numbers 1 through 12 are written on 12 slips of paper, with a different number on each paper slip, and placed in a bag. One
Naddik [55]
If you're asking for the number of digits smaller than 13 in the bag:12
8 0
3 years ago
Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In​ addition, there is
Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so P(A) = 0.13.

In​ addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. P(B/A) is the probability that the person is a male, given that he/she jogs. So P(B/A) = 0.156

The Bayes theorem states that:

P(B/A) = \frac{P(A \cap B)}{P(A)}

In which P(A \cap B) is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

So

P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0
3 years ago
5x -10x- 30= 10x solve for x
Andru [333]

Answer:

x=-2

Step-by-step explanation:

5x -10x- 30= 10x

-5x -30 = 10x

-30=15x

x=-2

8 0
3 years ago
Read 2 more answers
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