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3 years ago

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Lee made a map of his neighborhood on a coordinate plane. Each unit represent one block. He plotted the library at (4,5). He kno

ws his teacher lives seven blocks from the library. What are all the possible locations?

1 answer:

IRINA_888 [86]3 years ago

7 0

Answer:

The best place to jack off is by her window my dude

Step-by-step explanation:

You might be interested in

A) A club is considering changing its bylaws. In an initial straw vote on the issue, 24 of the 40 members of the club favored th

lora16 [44]

Answer:

38,38,380

Step-by-step explanation:

GIVEN: A club is considering changing its laws. In an initial straw vote on the issue, $24$ of the $40$ members of the club favored the change and $16$ did not. A committee of six is to be chosen from the $40$ club members to devote further study to the issue.

TO FIND: How many committees of six can be formed from the club membership.

SOLUTION:

Total number of members $=40$

Total members to be chosen $=6$

To select committee of $6$ members from $40$ $=^{40}C_6$

$=\frac{40!}{34!6!}$

$=38,38,380$

Hence 38,38,380 different committee can be formed.

7 0

3 years ago

In 2018, the number of students at The Villages High School was 975 and is increasing at a rate of 2.5% per year. Write and use

avanturin [10]

Answer:

$A(t)=975(1.025)^t$

In 2025,the number of students at the villages high school=1159

Step-by-step explanation:

We are given that in 2018

Number of students at the villages high school=975

Increasing rate,r=2.5%=0.025

We have to write and use of exponential growth function to project the populating in 2025.

$A_0=975,t=0$

According to question

Number of students at the villages high School is given by

$A(t)=A_0(1+r)^t$

Substitute the values

$A(t)=975(1+0.025)^t=975(1.025)^t$

t=7

Substitute the value

Then, the number of students at the villages high school in 2025

$A(7)=975(1.025)^7=1158.96\approx 1159$

8 0

3 years ago

Read 2 more answers

Using the formula V = l × w × h, find the volume of a right rectangular prism when the length of the prism is 45 cm, the width i

user100 [1]

Answer:

The volume of the right rectangular prism is 5400 cubic centimeter.

Step-by-step explanation:

Given : The length of the prism is 45 cm, the width is 12 cm, and the height is 10 cm.

To find : The volume of a right rectangular prism ?

Solution :

The formula used is $V=l\times w\times h$

Where, l is the length of the prism l=45 cm

w is the width of the prism w=12 cm

h is the height of the prism h=10 cm

Substitute the value in the formula,

$V=45\times 12\times 10$

$V=5400\ cm^3$

Therefore, The volume of the right rectangular prism is 5400 cubic centimeter.

7 0

3 years ago

Marilyn uses a credit card with a 19.9% APR compounded monthly to pay for car repairs totaling $991.38. She can pay $410 per mon

Leokris [45]

Marilyn's finance charge at the end of the first month will be
$991.38 × 0.199/12 = $16.44
The balance subject to the next month's finance charge will be
$991.38 +16.44 -410.00 = $597.82

The finance charge at the end of the second month will be
$597.82 × 0.199/12 = $9.91
The balance remaining after the second payment will be
$597.82 +9.91 -410.00 = $197.73

The finance charge applied at the end of the third month is
$197.73 × .199/12 = $3.28
so Marilyn can make one final payment of
$197.73 +3.28 = $201.01
to pay off the balance.

In all, Marilyn has paid 2×$410.00 +201.01 =
$1021.01 . . . . . . . . corresponds to the first choice

_____
In real life, Marilyn's credit card may not accrue any finance charge until after the first statement on which the charge appears. Thus the total cost of the purchase may be only $1004.02. The attached spreadsheet shows the beginning balance and the finance charges for each month for the two different scenarios.

8 0

3 years ago

What is the nth term?

kumpel [21]

Let $a_k$ denote the <em>k</em>th term of the sequence. Then

$a_k=a_1+d(k-1)$

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the <em>n</em>th term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago