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lana [24]
2 years ago
14

How much money will you have in 8 years if you invest $4000 at 2% compounded quarterly

Mathematics
2 answers:
laiz [17]2 years ago
6 0

Answer:

$4686.64

Step-by-step explanation:

here is the function 4000(1+0.02)^8

Mumz [18]2 years ago
5 0

Answer:

If you invest $4000 at 2% compounded quarterly you will make 4,694$.

Step-by-step explanation:

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B is the midpoint of AC and E' is the midpoint of BD. If A(-9,-4), C(-1, 6), and E(-4,-3), find the coordinates of D.
Ipatiy [6.2K]
The coordinates for D are (-4, -7)

First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint. 

x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4

y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1

Therefore B must be (-4, 1)

Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages. 

x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
-4 + Dx = -8 ---> add -4 to both sides
Dx = -4

y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
Dy = -7

So the coordinates for D must be (-4, -7)
5 0
3 years ago
Read 2 more answers
What is the greatest common factor of 12 and 90?
qwelly [4]
The greatest common factor (gcf) is 6.
4 0
3 years ago
Deon bought 26 pounds of rice for $11 . how many pounds of rice did he get per dollar?
ivanzaharov [21]
For $11, he bought = 26 pounds
so, for 1, it would be: 26/11 = 2.36

In short, Your Answer would be 2.36

Hope this helps!
5 0
3 years ago
For the x-values 1, 2, 3, and so on, the y-values of a function form
OlgaM077 [116]

Answer:

A. Decreasing linear

Step-by-step explanation:

6 0
3 years ago
Find the area of the region shaded in green. Use 3.14 to approximate pi.
8090 [49]

Answer:

254 cm² (to 3 s.f.)

Step-by-step explanation:

Area of shaded region

= area of large circle -area of smaller circle

\boxed{area \: of \: circle = \pi {r}^{2} }

Radius of large circle= 15cm

Radius of smaller circle= 12cm

Area of shaded region

= π(15²) -π(12²)

= 225π -144π

= 81π

= 81(3.14)

= 254.34

= 254 cm² (3 s.f.)

3 0
3 years ago
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