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Kobotan [32]
3 years ago
14

Determine which of he numbers are a. natural numbers, b. whole numbers, c. integers, d. positive integers, e. negative integers.

list all that apply.
1. -14, 9, 0, 53, 7.8, -626
Mathematics
2 answers:
Arada [10]3 years ago
7 0
Natural 9,53
whole 0,9,53
integers -14,9,0,53,-626
+integers 9,53
-integers -14,-626
Daniel [21]3 years ago
7 0

Naturals. Any whole number greater than 0. 1 9 53 The answer depends on what you have been told. Some text books include 0 as a natural number. Is 1. the question number? If it is then it obviously is not included.

Whole numbers 0 Plus the natural numbers given above.

Integers = -14 9 0 53 - 626

positive integers 9 53

negative integers - 14 - 626

You could get some of these incorrect. Everything depends on what you have been given for definitions.


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(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

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