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Alex Ar [27]
3 years ago
12

Solution description

Mathematics
1 answer:
Tpy6a [65]3 years ago
4 0

Answer: A solution is a homogeneous mixture of two or more substances. A solution may exist in any phase. A solution consists of a solute and a solvent. For example, in a saline solution, salt is the solute dissolved in water as the solvent.

Step-by-step explanation:

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Is 4 yards bigger than 13 feet
8_murik_8 [283]
1 yard = 3 feet

4 yards x 3 feet = 12 feet

12 feet is less than 13 feet


So False, 4 yards is <em>less than </em>13 feet

hope this helps
6 0
3 years ago
Read 2 more answers
In 1950, scientist estimated a certain animal population in a particular geographical area to be 6400 in 2000, the population ha
irina1246 [14]

Answer:

8,100

Step-by-step explanation:

7,200 - 6,400 = 800 increased in 50. Years

What percentage is 800 of 6,400 (%/100 = is/of)

x/100 = 800/6400 (cross multiply)

(800*100)/6400 = 12.50%

(12.50 * 7200)/100 = 900 increased

7,200 + 900 = 8,100

7 0
2 years ago
5 t-shirt cost R120.how much will 9t-shirt cost​
Whitepunk [10]

Step-by-step explanation:

given

5 t-shirts = R120

(5÷5) t - shirt = R(120÷5)

1 t-shirt = R24

(1x9) t-shirts = R(9x24)

= R216

3 0
3 years ago
HURRY I NEED HELP<br> I JUST NEED TO KNOW HOW TO DO THIS PLEASE <br> ILL GIVE 5 STARS AND STUFF PLS
timofeeve [1]

Answer:

On the left, it would be + 1 for each blank, and on the right it would also be +1 for each blank.

Step-by-step explanation:

They are asking for the intervals between each number.

Hope this helps!

3 0
2 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
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