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mina [271]
3 years ago
9

Nolan invested $8,100 in an account paying an interest rate of 8 3/4% compounded quarterly. Carter invested $8,100 in an account

paying an interest rate of 8 3/4% compounded annually. After 5 years, how much more money would Carter have in his account than Nolan, to the nearest dollar?
Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0

Answer:

61

Step-by-step explanation:

brainly said so lol

statuscvo [17]3 years ago
5 0

Answer:

I believe Nolan would have more money after 5 years, by $165

Step-by-step explanation:

Nolan:

A = 8100(1 + (.0875/4))^20

A = 12,486

Carter:

A = 8100 (1 + .0875)^5

A = 12,321

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C. 6/5 * 4

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6 0
3 years ago
If y = 3x^3 - 2x and dx/dt equals 3, find dy/dt when x = -2. Give only the numerical answer. For example, if dy, dt = 4, type on
Nadya [2.5K]

Answer:

 \frac{dy}{dt}  = 102

Step-by-step explanation:

<u>step(i)</u>

Given function y = 3 x³ - 2 x  ... (i)

Differentiating equation (i) with respective to 'x'

    \frac{dy}{dx} = 3 (3 x^{2} ) - 2(1)

Given x = -2

(\frac{dy}{dx} ) x_{=-2} = 3 (3 (-2)^{2} ) - 2(1)

(\frac{dy}{dx} ) x_{=-2} = 36 -2 =34

<u><em>Step(ii):-</em></u>

<u><em>we know that </em></u>

                     \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

Given    \frac{dx}{dt} = 3  and \frac{dy}{dx} = 34

                  \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

substitute values    \frac{dx}{dt} = 3  and \frac{dy}{dx} = 34  

           ⇒        34 = \frac{\frac{dy}{dt} }{3 }

cross multiplication , we get

                      \frac{dy}{dt} = 34( 3 ) = 102

<u><em>Final answer</em></u>:-

 \frac{dy}{dt} = 34( 3 ) = 102

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