The area enclosed is (2x)(600-2x).(2x)(600−2x)=1200x−4x2
In order to maximize we need the derivative to be equal to 0.y′=1200−8x=0
1200=8x
x=150
Therefore the sides for maximum area are 150*300.
<span>The area is: 45000</span>

Use the property of logs: a ln b = ln (b^a)
Also e and log are inverses, so the cancel each other
I got 9 and 3/8 because you would subtract 18 3/4 from 28 1/8
Answer:
Try 12.5, hopefully this helps :)