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3 years ago

Using right triangle below find the sine of angle B

Mathematics

2 answers:

Reil [10]3 years ago

7 0

Answer:

1/2

Step-by-step explanation:

sin = opposite/hypotenuse, so

sin(B) = $\frac{\sqrt{7} }{2\sqrt{7} }$ = 1/2

Naddik [55]3 years ago

7 0

Answer: the second option is the correct answer.

Step-by-step explanation:

Triangle ABC is a right angle triangle.

From the given right angle triangle,

AB represents the hypotenuse of the right angle triangle.

With m∠B as the reference angle,

BC represents the adjacent side of the right angle triangle.

AC represents the opposite side of the right angle triangle.

To determine Sine m∠B, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin B = √7/2√7

Sin B = 2

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