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madam [21]
3 years ago
5

a metal bar weighs 8.15 ounces. 93% of the bar is silver. how many ounces of silver are in the bar? (round to the nearest thousa

ndth)
Mathematics
2 answers:
masya89 [10]3 years ago
6 0
7.6 ounces of silver
fgiga [73]3 years ago
4 0

Answer: 7.560 ounces

Step-by-step explanation:

Given : The weight of a metal bar = 8.15 ounces

Also, it is given that : 93% of the bar is silver.

We can write 93% as 0.93  [To convert percent into decimal or fraction , we divide it by 100.]

Now, the amount of silver in the metal bar = 93% of 5.15 ounces

Replace 'of' by '×' and '93%' by '0.93' , we get

The amount of silver in the metal bar = 0.93\times8.15\text{ ounces}

7.5795\approx7.560\text{ ounces}

Hence, there are 7.560 ounces of silver in the metal bar.

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Jonah collects rainwater in a large barrel that weighs 30 pounds. When there are 10 gallons of water in the barrel, the total we
Serjik [45]
The first thing we are going to do for this case is define variables.
 We have then:
 x: number of gallons of water
 y: total weight
 We then have an equation of the form:
 y-yo = m (x - xo)

 Where,
 m = (y2 - y1) / (x2 - x1)

 Substituting values:
 m = (196.8 - 113.4) / (20 - 10)

m = 8.34
 We choose an ordered pair:
 (xo, yo) = (10, 113.4)

 Substituting values:
 y-113.4 = 8.34 (x - 10)

 Rewriting:
 y = 8.34x - 83.4 + 113.4

y = 8.34x + 30
 Answer:
 
y = 8.34x + 30
8 0
3 years ago
A rectangular prism has side lengths of 4 inches, 6 inches, and 7 inches. If all side lengths are multiplied by 5, what happens
alexandr402 [8]
Most likely your answer would be A
4 0
3 years ago
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Solve for b.<br><br> 3 (b−4 )+ 5b = 44<br><br><br> b =
Sergeu [11.5K]
B=7
3(b-4)+5b=44
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7 0
2 years ago
A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength
irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

<u><em>Let </em></u>\bar X<u><em> = sample mean comprehensive strength</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean comprehensive strength = 5500 psi

            \sigma = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P(\bar X > 4985 psi)

    P(\bar X > 4985 psi) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{4985-5500}{\frac{100}{\sqrt{9} } } ) = P(Z > -15.45) = P(Z < 15.45)

                                                                  = <u>0.99999</u>

<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>

4 0
3 years ago
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Stels [109]

Answer:

752

Step-by-step explanation:

IN these type of questions we put the numbers in descending order

3 0
3 years ago
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