The answer is DS-30A. The Roland DS30A is a 24-bit Digital Reference Monitor which can add pristine 24-bit/96kHz. They are small speakers.
Answer: Concurrent programs are the programs that execute at the same point of time. They are simultaneous in nature with other concurrent programs.They are executed with the help of threads to achieve the concurrency without the issue of scheduling. They are consider long running programs.
The program that has the low execution time compared with all other programs gets executed first.If the case of no progress is seen then another thread is executed.This type of execution gives the non- deterministic situation in which the possibility of leading completion of any particular program cannot be determined.
Answer:
Options A and C.
Explanation:
In Oracle Cloud Infrastructure the two options which allows you to increase disk performance are;
1. Terminate the compute instance preserving the boot volume. Create a new compute instance using a VM Dense IO shape using the boot volume preserved.
2. Create a backup of the boot volume. Create a new compute instance a VM Dense IO shape and restore the backup.
Answer:
"The value of the variable will remain the same which is already have when the sub-processor is called".
Explanation:
The above question said that:-
void fun(int a)
{
a=a+1;
}
void main()
{
int a=5;
fun(a);
}
//what will be the value of a in the main function after the fun function is excuted.
- Then the answer is: the value of a will be 5 in the main function.
- It is because when the fun function is called, then a variable that is defined in the fun function is a local variable for fun function. That scope after the fun function is null.
- The a variable inside the fun function is a different variable and the main function a variable is also a different variable.
- So when the user prints the value of a variable inside the fun function, it will give the result as 6.
- But when he prints the value of a variable inside the main function, then it will give the value as 5.
Answer:
The solution code is written in Java.
- public static void swapArrayEnds(int myArray[]){
- int lastIndex = myArray.length-1;
- int temp = myArray[0];
- myArray[0] = myArray[lastIndex];
- myArray[lastIndex ] = temp;
- }
Explanation:
First create the swapArrayEngs method that take one input array parameter (Line 1).
Since we need to swap the first and last element of the array, we need to get the first index and last index of the array. The first index is 0 and the last index can be calculated by subtracting the length of array from 1 (Line 2).
Next, we can create a temp variable to hold the value of the first element (Line 3). Then we use the lastIndex the get the value of last element and assign it to the first element of array (Line 4). Lastly, we assign the temp (holding the initial first element value) to the last element of array (Line 5).
