Answer:

Step-by-step explanation:
![\sf 3a^5-18a^3+6a^2\\\\HCF = 3a^2\\\\Take \ 3a^2 \ common\\\\= 3a^2(a^3-6a+2)\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%203a%5E5-18a%5E3%2B6a%5E2%5C%5C%5C%5CHCF%20%3D%203a%5E2%5C%5C%5C%5CTake%20%5C%203a%5E2%20%5C%20common%5C%5C%5C%5C%3D%203a%5E2%28a%5E3-6a%2B2%29%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
The answer is -28
(sorry if i get this wrong)
Answer:
x = 8
Step-by-step explanation:
Let's solve your equation step-by-step.
5x−6=3x+10
Step 1: Subtract 3x from both sides.
5x−6−3x=3x+10−3x
2x−6=10
Step 2: Add 6 to both sides.
2x−6+6=10+6
2x=16
Step 3: Divide both sides by 2.
2x
/2
=
16/
2
x=8
Answer:
False
Step-by-step explanation:
Given

Required
True or False
The above numeral can be split as follows:

X means 10 and L means 50.
But because X (10) which is smaller comes before L (50), XL is executed as:


In Roman numerals;

Substitute 40 for XL and 4 for IV.


Hence;
<em />
<em> is false</em>