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ElenaW [278]
3 years ago
10

What's the answer to both when simplifying the two radical expression?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
7 0
( \sqrt{x} +2 \sqrt{5})*( \sqrt{x} -2 \sqrt{5}) =  \\  \\   ( \sqrt{x})^2- (\sqrt{x} *2 \sqrt{5})+(2 \sqrt{5}* \sqrt{x}) -(2 \sqrt{5})^2 =  \\  \\    x- 2\sqrt{5} \sqrt{x}+2 \sqrt{5} \sqrt{x} -(4*5)=  \\  \\   x -(4*5)=  \boxed{x-20}   \\  \\

( \sqrt{x}+ \sqrt{5}) ^2=   \\  \\   ( \sqrt{x})^2+2* \sqrt{x}* \sqrt{5} + (\sqrt{5}) ^2=   \\  \\   \boxed{  x +2 \sqrt{5x}+5}
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Based on the polynomial remainder theorem, what is the value of the function when x=−6 ?
Vaselesa [24]
ANSWER

f( - 6) =  10


EXPLANATION

The given function is
f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40

According to the remainder theorem,

f( - 6) = R
where R is the remainder when
f(x)

is divided by
x + 6


We therefore substitute the value of x and evaluate to obtain,

f( - 6) =  { (- 6)}^{4}  + 8 {( - 6)}^{3}  + 10 { (- 6)}^{2}  - 7( - 6)+ 40




f( - 6) =  1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40




f( - 6) =  1296  - 1728 + 360  + 42+ 40



This will evaluate to,


f( - 6) =  10


Hence the value of the function when
x =  - 6

is
10



According to the remainder theorem,
10
is the remainder when

f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40
is divided by
x + 6
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