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Wittaler [7]
3 years ago
14

Which of the following describes an interaction in which one organism kills and eats another?

Biology
1 answer:
ss7ja [257]3 years ago
4 0

Answer: Predation

Explanation:

Predation is the biological interaction between two organisms whereby one benefits by feeding on the other. The organism that kills and eats another is known as Predator e.g lion, I while the other that is eaten is known as prey, e.g rabbit

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In a Venn diagram, the separate circles contain characteristics unique to each item being compared and the intersections contain
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When combining more than two circles in a Venn diagram you have to actually mix in the colors where the intersections are so that you will be able to tell their differences.

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What do you think is the most important reason for learning about environmental systems?
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How does an increase in available food increase genetic diversity?
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Explanation:

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Spontaneous reactions _____. always result in increased disorder of the system always take place at a rapid rate always release
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The correct answer is that it "naturally favor the formation of products".
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Bacteria and other microbes can be used to "clean up" an oil spill by breaking down oil into carbon dioxide and water. Two sampl
aksik [14]

Answer:

For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

Explanation:

The composition of nitrogenous bases in DNA is calculated using the suggestions proposed by the results of the experiment performed by Erwin Chargaff.

He found that in a DNA sample the composition of purine to pyrimidine is 1:1. This indicates that the amount of purine equals pyrimidine. This can be presented as purines + pyrimidines= 100. Also, adenine binds thymine and cytosine binds guanine.

In the given question,  

<u>For sample A </u>

A= 17.7 %, Therefore, thymine will be = 17.7 %,

A+T= 35.40%

Now, G+C=100- 35.40%

G+C= 64.60%

content of G= 64.60/2= 32.30%

content of C= 32.30%

<u>For sample B </u>

T=28.9%, A will be= 28.9%

A+T= 57.80%

G+C=100-57.80%

G+C= 42.20%

Thus content of G will be= 42.20/2=21.10

content of C= 21.10%

Thus,  

For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

6 0
3 years ago
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