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Alik [6]
3 years ago
14

The monthly average temperature, T, for San Francisco is usually within 7.5 degrees and 56.5 degrees, inclusive. What is the mon

thly average temperature? (Use either an equation or an inequality to model this situation.)
Mathematics
1 answer:
erica [24]3 years ago
5 0
49 es la temperatura mensual
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Change 2.36 to a mixed number and reduced to lowest terms
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ASAP! I WILL MARK BRAINLIST ! 38 POINTS STEP BY STEP PLEASEE STEPS NEEDED!
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Answer:

A) Length = 110.4 mm and width = 62.1 mm

B) A = 6855.84 mm²

C) length = 114.7 mm

width = 55.8 mm

Area = 6400.26 mm²

D) Screen with aspect ratio of 16:9 is bigger

Step-by-step explanation:

A) We are told that the aspect ratio of the phone screen = 16:9. This means that the ratio of the length to the width of the screen is 16:9.

To find the side length, we will say that;

length = 16x

width = 9x

Thus, since the edges are perpendicular, then we can use pythagoras theorem since we know that the diagonal is 127 mm

Thus;

(16x)² + (9x²)] = 127²

256x² + 81x² = 16129

337x² = 16129

x² = 16129/337

x = √(16129/337)

x = 6.9

Thus;

length = 16x = 16 × 6.9 = 110.4 mm

width = 9x = 9 × 6.9 = 62.1 mm

Length = 110.4 mm and width = 62.1 mm

B) area of screen is;

A = length × width

A = 110.4 × 62.1

A = 6855.84 mm²

C) We are told that the aspect ratio is now 18.5:9.

Thus;

length = 18.5x

width = 9x

Thus;

(18.5x)² + (9x²)] = 127²

342.25x² + 81x² = 16129

423.25x² = 16129

x² = 16129/423.25

x = √(16129/423.25)

x = 6.2

length = 18.5x = 18.5 × 6.2 = 114.7 mm

width = 9x = 9 × 6.2 = 55.8 mm

Area = 114.7 × 55.8 = 6400.26 mm²

D) Screen with aspect ratio of 16:9 is bigger

8 0
2 years ago
Which equation represents the general from circle w
aev [14]

d. \:  {x}^{2}  +  {y}^{2}  - 4x - 6y - 3 = 0 \\  \\ x = 2 +  \infty  \sqrt{(y - 7)(y + 1)} 2 -  \infty  \sqrt{(y - 7)(y + 1)}

8 0
3 years ago
Need help answering this question!!!!
Y_Kistochka [10]
For this case we use the following formula
Area of Sector = Area * radians of sector / 2 * pi radians
Where,
Area: it is the area of the complete circle.
We have then:
Area = pi * r ^ 2
Area = pi * (6) ^ 2
Area = 36pi
Substituting values:
5pi = 36pi * radians of sector / 2 * pi
Clearing:
radians of sector = ((5pi) * (2pi)) / (36pi)
radians of sector = (10pi ^ 2) / (36pi)
radians of sector = (10pi) / (36)
radians of sector = (10/36) pi
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ArbitrLikvidat [17]

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Step-by-step explanation:

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