In the equation below, what is the value of b? 4(x-2)^2-7=ax^2+bx+c

1 answer:

4 0

We have 4(x^2 - 2x + 4) - 7 = 4x^2 - 8x + 16 - 7 = 4x^2 - 8x + 9;
So, 4x^2 - 8x + 9 = ax^2+bx+c ;
The value of b is -8.

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valentinak56 [21]

Answer:

Step-by-step explanation:

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Where

a is the first term, and

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First term:

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Second term:

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}$

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Thus we have a = 3 and r = 1/4. Plugging into the formula of the infinite sum, we get:

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Answer:

hope I helped also good bless u and your family

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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