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3 years ago

10

Isabell is thinking of a even number between 234 and 250 the sum of the digits is double the digit in the ones place what is Isa

bell's number

1 answer:

Lelu [443]3 years ago

5 0

Answer:

246.

Step-by-step explanation:

Let the number be 2xy, then

2 + x + y = 2y and y must be even because the whole number is even.

y = 2 + x .

Now x must be even because y is even.

The only 2 numbers which fit are x = 4 and y = 6 so the number is 246.

Checking: 2+4+6 = 12 and 12 = 2*6.

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PLZ HELP ASAP INSCRIBED QUADRILATERALS

Natasha2012 [34]

Opposite angles of an inscribed quadrilateral are supplementary, that is, they add up to 180 degrees. For this quadrilateral, Q + A = 180, and similarly, U + D = 180. Since we are given U = 106, therefore:
106 + D = 180
D = 74 degrees.

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3 years ago

Please help me, I don't know how to solve it

goblinko [34]

Answer:

2a-3 and a+4

Step-by-step explanation:

Given the equation

2a²+8a -15 = 3a - 3

We are to find one of its factors

Equate the expression to zero

2a²+8a -15 = 3a - 3

2a²+8a -15 - 3a + 3 = 0

Collect the like terms

2a²+8a - 3a - 15 + 3= 0

2a²+5a - 12= 0

Factorize

2a²+8a-3a - 12= 0

2a(a+4)-3(a+4) = 0

(2a-3)(a+4) = 0

Hence the factors are 2a-3 and a+4

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3 years ago

A trapezoid on a square. The square has side lengths of 12 feet. The trapezoid has a base of 6 feet, height of 3 feet, and top s

german

Answer:

159

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2

saul85 [17]

$\large\underline{\sf{Solution-}}$

<u>Let us assume that:</u>

$\sf \longmapsto x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ... \infty } } }$

We can also write it as:

$\sf \longmapsto x = \sqrt{6 + x }$

Squaring both sides, we get:

$\sf \longmapsto {x}^{2} =6 + x$

$\sf \longmapsto {x}^{2} - x - 6 =0$

By splitting the middle term:

$\sf \longmapsto {x}^{2} - 3x + 2x - 6 =0$

$\sf \longmapsto x(x - 3) + 2(x - 3 ) =0$

$\sf \longmapsto (x+ 2)(x - 3 ) =0$

<u>Therefore:</u>

$\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}$

$\sf \longmapsto x = - 2,3$

<u>But x cannot be negative. </u>

$\sf \longmapsto x = 3$

Therefore, the value of the expression is 3.

$\large\underline{\sf{Verification-}}$

Given:

$\sf\longmapsto x=3$

We can also write it as:

$\sf\longmapsto x = \sqrt{9}$

$\sf\longmapsto x = \sqrt{6+3}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{9}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}$

This pattern will continue.

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}$

7 0

3 years ago

What is the answer to 2(14/2R - 15+2R - 3/2+7R)-4

sleet_krkn [62]

I hope this helps you

2.(7R-15+2R-3/2+7R)-4

2. (16R-33/2)-4

2.16R-2.33/2-4

32R-33-4

32R-37

6 0

4 years ago

Read 2 more answers