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Fittoniya [83]
3 years ago
14

In which quadrant does the terminal side of a 314° angle lie?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
5 0
We know that

I Quadrant -----> <span>for angles between 0 degrees and 90 degrees
</span>II Quadrant-----> for angles between 90 degrees and 180 degrees
III Quadrant-----> for angles between 180 degrees and 270 degrees
iV Quadrant-----> for angles between 270 degrees and 360 degrees

therefore

314 degrees belong to the IV quadrant

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1 is a parallelagram

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An amount of $25,000 is borrowed for 9 years at 9% interest, compounded annually. If the loan is paid in full at the end of that
Aleks04 [339]

Answer:

  $36,566

Step-by-step explanation:

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Solve each system using SUBSTITUTION. Remember to check!
Annette [7]

Answer:

\left \{ {{x=3} \atop {y=-7}} \right.

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We can directly substitute y of the first equation to the second equation.

-2x - 1 = 3x - 16

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x = 3

Substituting back to any of the two equations, we get y = -2(3)-1 = -7.  If you check with the second equation, y = 3(3)-16 = -7 as well.

Therefore \left \{ {{x=3} \atop {y=-7}} \right..

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Many people use scanners to read documents and store them into pdf file. To help determine which brand of scanner to buy, a stud
konstantin123 [22]

The data is missing in the question. The data is provided below :

Document : 1     2      3      4      5     6      7      8

Brand A       17  29    18    14    21   25    22    29

Brand B       21  38    15    19    22   30    31   37

Solution :

State of the hypothesis of the null hypothesis and alternate hypothesis.

Null hypothesis : $h_A = h_B$

Alternate hypothesis : $h_A > h_B$

These hypothesis is a one tailed test. The null hypothesis will get rejected when the mean difference between the sample means is very small.

Significance level = 0.05

Therefore the standard error is :  $SE = \sqrt{(\frac{s^2_1}{n_1})+(\frac{s^2_2}{n_2})}$

                                                         = 3.602

And the degree of freedom, DF = 14

$t=\frac{(x_1-x_2)-d}{SE}$

 = -1.319

Here, $s_1$ = standard deviation of the sample 1

        $s_2$ = standard deviation of the sample 2

         $n_1$ = size of the sample 1

        $n_2$ = size of the sample 2

         $x_1$ = mean of the sample 1

        $x_2$ = mean of the sample 2      

          d = the hypothesis difference between the population mean

The observed difference in a sample means t static of -1.32. From t distribution calculator to determine P($t \leq -1.32$) = 0.1042  

Since the P value of 0.1042 is greater than significance level o 0.05, we therefore cannot reject the null hypothesis.

But from the test, we have no sufficient evidence that supports that Brand A is better than Brand B.      

8 0
3 years ago
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