3 years ago

Calculate the slope between the given points

Mathematics

1 answer:

gulaghasi [49]3 years ago

4 0

(9-6)/(18-10)= 3/8
The slope is 3/8

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A force of 4 pound acts in the direction of 48degree to the horizontal. The force moves an object along a straight line from the

Dafna11 [192]

Answer:

<u>Work Done = 27.66 Joules</u>

Step-by-step explanation:

The work done is:

$W=F*d*Cos \theta$

Where

F is the fore

d is the distance moved

$\theta$ is the angle

The force is "4"

The distance is the distance from (1,7) to (8,10)

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$\sqrt{(10-7)^2+(8-1)^2}\\=\sqrt{3^2+7^2}\\\sqrt{58}$

The angle is gotten by the formula:

$Cos\phi = \frac{Force in x direction}{Distance}\\Cos\phi = \frac{8-1}{\sqrt{58}}\\Cos\phi=\frac{7}{\sqrt{58}}\\\phi = Cos^{-1}\frac{7}{\sqrt{58}}\\\phi = 23.21$

So, now:

$\theta = 48 - 23.21 = 24.79$

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3 years ago

What is the slope of the line whose equation is –48 = 2x − 8y?

alexgriva [62]

-48 = 2x - 8y
-24 = x - 4y
4y = x + 24
y = (1/4)x + 6

Slope of the line
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A - drawing a red 8

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$P(A|B)=\dfrac{P(A\cap B)}{P(B)}\\\\ |\Omega|=52\\ |A\cap B|=2\\ |B|=4\\\\ P(A \cap B)=\dfrac{2}{52}=\dfrac{1}{26}\\ P(B)=\dfrac{4}{52}=\dfrac{1}{13}\\\\ P(A|B)=\dfrac{\dfrac{1}{26}}{\dfrac{1}{13}}=\dfrac{1}{26}\cdot13=\dfrac{1}{2}$

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