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alina1380 [7]
3 years ago
9

Given the expression -7+6i/2+3i , perform the indicated operation and write the answer in the form a + bi.

Mathematics
1 answer:
Andre45 [30]3 years ago
8 0
\dfrac{-7+6i}{2+3i}\times\dfrac{2-3i}{2-3i}=\dfrac{(-7+6i)(2-3i)}{(2+3i)(2-3i)}=\dfrac{4+29i}{4-9i^2}=\dfrac4{13}+\dfrac{29}{13}i
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SV is a midsegment of △RTU.<br> If TU=y+38 and SV=y–9, what is the value of y?
pav-90 [236]

Answer:

y = 56

Step-by-step explanation:

the midsegment SV is half the length of the side TU , that is

y - 9 = \frac{1}{2} (y + 38) ← multiply both sides by 2 to clear the fraction

2y - 18 = y + 38 ( subtract y from both sides )

y - 18 = 38 ( add 18 to both sides )

y = 56

8 0
2 years ago
How to solve z+2/z-3=5/-3
OLEGan [10]
(z+2)= (z-3)(5/-3)
z+2 = 5z/-3 +5
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5 0
3 years ago
Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2
Marat540 [252]

Given:

The point, (4, -3)

The line,

y=\frac{1}{2}x+5

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

m=\frac{1}{2}

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

y-y_1=m(x-x_1)

Substitute the point and slope we get,

\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}

Hence, the equation in slope-intercept form for the line is,

y=\frac{1}{2}x-5

8 0
1 year ago
I will mark as BRAINLIEST and 8 points if correct.
g100num [7]

Answer:

the answer is d

Step-by-step explanation:

6 0
3 years ago
jenns age is 3 years less than marks age the sum of their ages is 30 let m be marks age find Jenna age
melamori03 [73]

Answer:

you could do 27+x=30

Step-by-step explanation:

7 0
3 years ago
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