All categories

3 years ago

Given the expression -7+6i/2+3i , perform the indicated operation and write the answer in the form a + bi.

1 answer:

8 0

$\dfrac{-7+6i}{2+3i}\times\dfrac{2-3i}{2-3i}=\dfrac{(-7+6i)(2-3i)}{(2+3i)(2-3i)}=\dfrac{4+29i}{4-9i^2}=\dfrac4{13}+\dfrac{29}{13}i$

You might be interested in

Based on the data, which table shows a constant of proportionality of 3 for the ratio of amps to guitars

Dafna1 [17]

Answer:

table d

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

-\frac{4\left(x+3\right)}{5}=4x-12

Keith_Richards [23]

Answer:

huh

Step-by-step explanation:

6 0

3 years ago

Lisa has a certain amount of money. She spent 39 dollars and has 3/4th of the original amount left. How much money did she have

harina [27]

If $\frac { 3 }{ 4 }$ is left, that means $\frac { 1 }{ 4 }$ was spent. So $\frac { 1 }{ 4 }$ of the total amount is equal to 39.. Let's say x to the total amount. $\frac { 1 }{ 4 } \cdot x=39\\ x=4\cdot 39\\ x=156\\$

4 0

3 years ago

Read 2 more answers

Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

2 years ago

a patient was supposed to take 560 mg of medicine but took on The 420 mg what percent of medicine does she take

Sav [38]

You need to set the correct porportion. x is the percent value you want to find. 100 is the maximum percentage. 420mg is what was taken out of the maximum 560mg dose.

$\frac{x}{100} \times \frac{420}{560}$

You will cross multiple.

$560x = 42000$

you will divide 42000 by 560

$\frac{560x}{560} = \frac{42000}{560}$
$x = 75$

The complete answer will be: The patient took 75% of the 560mg dose of medication.

5 0

3 years ago