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3 years ago

10^log23 =?

Mathematics

1 answer:

erik [133]3 years ago

8 0

10^log 23 = 23 .
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Please show me how to solve for Xsquared - 21.75X = -15.75. I have the solution but do not know how to solve it.

Andreas93 [3]

$x^2-21.75x=-15.75 \\
x^2-21.75x+15.75=0$

Use the quadratic formula:
$x^2-21.75x+15.75=0 \\ \\
a=1 \\ b=-21.75 \\ c=15.75 \\ b^2-4ac=(-21.75)^2-4 \times 1 \times 15.75=473.0625-63=410.0625 \\ \\
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x=\frac{21.75-20.25}{2} \ \lor \ x=\frac{21.75+20.25}{2} \\
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x=\frac{3}{4} \ \lor \ x=21 \\
\boxed{x=\frac{3}{4} \hbox{ or } x=21}$

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3 years ago

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3 years ago

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Step-by-step explanation:

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3 years ago

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Solve: 0.2c + 0.69 = 1.37 c = _____

iVinArrow [24]

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3 years ago

I need help I don’t know how that’s not right.

Leviafan [203]

Answer: v=-81.92

Step-by-step explanation:

$\displaystyle\\7+\frac{v}{8} =-3.24\\\\7+\frac{v}{8}-7 =-3.24-7\\\\\frac{v}{8} =-10.24\\\\\frac{v}{8} =-10.24$

Multiply both parts of the equation by 8:

$\displaystyle\\(\frac{v}{8})(8)=(-10.24)(8) \\\\v=-81.92$

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1 year ago