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kari74 [83]
3 years ago
9

Merle opened a new savings account she deposited 40,000 at 10% compounded semiannually at the start of the fourth year merle dep

osits an additional 20,000 that is also compounded semiannually at 10% at the end od six years the balance in merle account is
Mathematics
1 answer:
UNO [17]3 years ago
4 0

happy first question!!!!

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16. Solve for the angle x.<br> cos(¹/2x) = ¹/2
Basile [38]

Answer:

We know that ,

\rightarrow \tt \cos( \frac{\pi}{3} )  =  \frac{1}{2}

So ,

\:  \rightarrow \tt \cos( \frac{1}{2}x )    =  \cos( \frac{\pi}{3} )  \\  \\   \rightarrow \tt \frac{1}{2}.x =  \frac{\pi}{3}  \\  \\ \rightarrow \tt x =  \frac{2\pi}{3}

we can add 2 pi to it since there will be no change in the value

Also,

\: \rightarrow \tt  \cos( \frac{14\pi}{6} )  =  \frac{1}{2}  \\  \\  \\ \rightarrow \tt \frac{1}{2}  x =  \frac{14\pi}{6}  \\  \\ \rightarrow \tt x =  \frac{7\pi}{3}

Answer : Option B

6 0
2 years ago
What is the sum of the interior angels of a regular polygon with 7 sides. choices are
Oksi-84 [34.3K]

Sum of Interior Angles of any poligon, where n is the number of sides: =

(n-2) × 180°

---------------------

(7 - 2) * 180° =

5 * 180 =

900°

[d]

7 0
3 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0
4 years ago
What is the square root of 51.84​
bija089 [108]
The square root of 51.84 is 7.2
7 0
3 years ago
For questions 1 - 2, use the following functions:
natita [175]

Answer:

fx+gx=5x-11

fx-gx=x-3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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