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kari74 [83]
3 years ago
9

Merle opened a new savings account she deposited 40,000 at 10% compounded semiannually at the start of the fourth year merle dep

osits an additional 20,000 that is also compounded semiannually at 10% at the end od six years the balance in merle account is
Mathematics
1 answer:
UNO [17]3 years ago
4 0

happy first question!!!!

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I need to find what is equal to m
USPshnik [31]

Answer: 0

Step-by-step explanation:

Point A = (3 , 4)

Point B = (7 , 4)

\frac{yB - yA}{xB - xA}  = \frac{0}{5}

5 0
3 years ago
Just wondering is 71 a PRIME number? ≡≡≡
Sergeu [11.5K]
Yes 71 is a Prime Number
7 0
3 years ago
Read 2 more answers
5 Find 6 in Surface Area​
iVinArrow [24]

Answer:

8 x 6 = 48

48 divided by 2 = 24

24 x 2 = 48

10 x 12 = 120

120 x 2 = 240

8 x 12 = 96

Add all given areas:

48 + 96 + 240 = 384 in2 is your answer.

3 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
4 years ago
On factorising 14pq + 35pqr. we get?
Anna71 [15]

Answer:

7pq( 2 + 5r)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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