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2 years ago

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Merle opened a new savings account she deposited 40,000 at 10% compounded semiannually at the start of the fourth year merle dep

osits an additional 20,000 that is also compounded semiannually at 10% at the end od six years the balance in merle account is

1 answer:

UNO [17]2 years ago

4 0

happy first question!!!!

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What's the answer???!

Ksivusya [100]

50 degrees since a triangle is 180 degrees and the other 2 are 40 and 90

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3 years ago

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Help solve #2 please

borishaifa [10]

its pithagoreon so

c^2= a^2+ b^2

c^2= 32^2 +24^2

c^2= 1,024+576

c^2= 1600

c= $\sqrt{1600\\$ = 40

5 0

3 years ago

Thelma spent 1/6 of her weekly allowance on dog toys. 1/4 on a dog collar and 1/3 on dog food. What fraction of her weekly all

Paladinen [302]

To figure out you would first find a common factor with would be 12. After that 1/4 would be 3/12, 1/3 would be 4/12 and 1/6 would be 2/12. Next you just add all the numbers and get 9/12 then the remainder is you answer which comes to be 3/12 or 1/4. Hope that helps:)

3 0

3 years ago

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Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

<u>Statement 1: </u>"The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

$178=x^2+3x-y\\ \\ -6=4x-3y$

8 0

3 years ago

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Alice's grandfather is showing Alice his apple

Amanda [17]

There are 156 rows of trees altogether.

<u>Step-by-step explanation:</u>

Given that for every 11 rows of Red delicious , they plant 3 rows of Royal Gala.

Thus for 1 row of Royal Gala there would be 11/3 rows of Red delicious.

Number of rows of Royal Gala=18

$corresponding\ number\ of\ Red\ delicious\ = 11/3 \times 18=11\times 6=66$

For 11 rows of red delicious,they plant 7 rows of yellow delicious.

Thus for 1 row of Red delicious,there would be 7/11 rows of yellow delicious.

For 66 rows of red delicious there would be

$7/11\times66=7\times 6=42 rows\ of\ yellow\ delicious$

For 11 rows of red delicious,they plant 5 rows of Braeburn

for 1 row of red delicious,they would plant 5/11 rows of Braeburn.

For 11 rows of red delicious,they would plant

$5/11\times 66=5\times 6=30\ rows\ of\ braeburn$

Total rows of trees=66+42+30+18=156

8 0

3 years ago