1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kari74 [83]
3 years ago
9

Merle opened a new savings account she deposited 40,000 at 10% compounded semiannually at the start of the fourth year merle dep

osits an additional 20,000 that is also compounded semiannually at 10% at the end od six years the balance in merle account is
Mathematics
1 answer:
UNO [17]3 years ago
4 0

happy first question!!!!

You might be interested in
What does e^-infinity and e^infinity equal to? Explain your answer
Colt1911 [192]
Remember that e is equals to 2.717 something and to find the value of the infinities, you must consider there signs. So the e^infinity approaches to infinity while the e^-infinity approaches to zero. I hope you are satisfied with my answer and feel free to ask for more 
8 0
3 years ago
What is 1wfqWR x5nrznzrnzrn
Alborosie

Answer:

could you type that again? I don't understand

7 0
3 years ago
Read 2 more answers
Which statement accurately explains whether a reflection over the X-axis and a 180° rotation would map figure ACB onto itself?​
Arlecino [84]

Using transformation rules, it is found that the correct option is:

No, A'C'B' is located at A(-1,1), C'(-3,4) and B'(-5,1).

--------------------

  • The transformation rule for a reflection over the x-axis is (x,y) \rightarrow (x,- y)
  • The transformation rule for a rotation of 180º is (x,y) \rightarrow (-x,-y)

  • After the reflection over the x-axis: (x,y) \rightarrow (x, -y)
  • Taking the reflection, and rotating: (x,-y) \rightarrow (-x, -(-y)) = (-x,y).
  • Not the same rule, that is, (x,y) \rightarrow (x,y), so it would not map figure onto itself.
  • A(1,1) would be mapped to A(-1,1), for example, thus, the correct option is:

No, A'C'B' is located at A(-1,1), C'(-3,4) and B'(-5,1).

A similar problem is given at brainly.com/question/10547006

8 0
2 years ago
Read 2 more answers
A point G is 40m away from a building, which is 15m high. What is the angle of elevation to the top of the building from G?
stepladder [879]
Ф is the angle of elevation to the topo of the building from G.
length of leg adyacent to angle Ф=40m
length of leg opposite to angle Ф=15 m
tan Ф=leg opposite / leg adyacent=15/40=0.375
Ф=arctan 0.375=20.56º

The angle of elevation to the top of the building from G is 20.56º.
8 0
3 years ago
Point A is found at (-3, -3). Find the sin at that point.
Inga [223]

Answer:

B. -√2/2.

Step-by-step explanation:

This is in the third quadrant  so the sine will be negative.

The hypotenuse =  √ [( -3)^2 + (-3)^2]

= √18 = 3√2.

Therefore the sine =  -3 / 3√2.

= -1 / √2

= -√2/2..

4 0
4 years ago
Other questions:
  • CAN SOME ONE HELP ME CORRECT ANSWERS ONLY WILL GIVE BRAINLIEST
    11·1 answer
  • What are the properties of addition?
    8·1 answer
  • Because a square is a rectangle,it must have.Because a square is a trapezoid,it must have.Because a square is a quadrilateral,it
    15·1 answer
  • Is 5feet greater less or equal to 60 inches
    6·2 answers
  • Find the unique solution to the following linear system X = (0 -1 2 3)X + (e' -e') <br> X(0)=(5 4)
    11·1 answer
  • Cross Section
    8·1 answer
  • If 50% is 10 what is 100%​
    15·2 answers
  • 18 divided by under root 18
    8·1 answer
  • Answer plsss........ ​
    7·1 answer
  • What is the measure of ZXYZ?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!