Answer:
Elaine is the outside hitter in Freshman Year
Kelly is the setter in Junior Year
Shannon is the middle blocker in Sophomore Year
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The graph located in the upper right corner of the image attached shows the graph of y = 3[x]+1.
In order to solve this problem we have to evaluate the function y = 3[x] + 1 with a group of values.
With x = { -3, -2, -1, 0, 1, 2, 3}:
x = -3
y = 3[-3] + 1 = -9 + 1
y = -8
x = -2
y = 3[-2] + 1 = -6 + 1
y = -5
x = -1
y = 3[-1] + 1 = -3 + 1
y = -2
x = 0
y = 3[0] + 1 = 0 + 1
y = 1
x = 1
y = 3[1] + 1 = 3 + 1
y = 4
x = 2
y = 3[2] + 1 = 6 + 1
y = 7
x = 3
y = 3[3] + 1 = 9 + 1
y = 10
x y
-3 -8
-2 -5
-1 -2
0 1
1 4
2 7
3 10
The graph that shows the function y = 3[x] + 1 is the one located in the upper right corner of the image attached.
We have that
A(-2,-4) B(8,1) <span>
let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3
we know that
A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so
step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2
step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2
the coordinates of point M is (2,-2)
see the attached figure
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Answer:
Option B and C are correct.
Step-by-step explanation:
Inverse function: If both the domain and the range are R for a function f(x), and if f(x) has an inverse g(x) then:
for every x∈R.
Let and
Use logarithmic rules:
then, by definition;
=
Similarly;
for and
then, by definition;
=
Similarly,
g(f(x)) = x
Therefore, the only option B and C are correct. As the pairs of functions are inverse function.