You have 36 roses because you have eight more pink than red so that means you have 22 pink and 14 red. 22 + 14 = 36
Answer:
1. 6pi or 18.84cm
2. 20pi or 62.8cm
3. 13pi or 40.82cm
4. 9.5pi or 29.83cm
5. You calculate the circumference of a circle with the expression 2pi(r). r stands for the radius. You can also use pi(d), or pi x diameter.
7. You would use 2pi(r) to find the circumference of a circle when given the value of the circle's radius.
8. You would use pi(d) to find the circumference of a circle when given the value of the circle's diameter.
Answer:
5 more wagons
Step-by-step explanation:
378/21 =18
18 - 13= 5
how many 3 element subsets of {1, 2, 3, 4, 5, 6, 7, 8, ,9, 10, 11} are there for which the sum of the elements in the subset is
AURORKA [14]
Answer:
There are 155 ways in which these elements casn occur.
Step-by-step explanation:
We want 3 element subsets whose sum are multiples of 3
1+2+3= 6
1+2+6= 9
1+2+9= 12
1+9+11=21
1+3+5=9
1+4+8=12
1+5+6=12
1+6+8=15
1+7+10=18
1+8+9=18
1+9+11=21
2+3+7=12
2+4+6=12
2+4+9=15
2+5+11=18
2+6+7=15
2+7+9=18
2+8+5=15
2+8+11=21
2+9+10=21
3+6+9= 18
3+9+11=21
3+10+11=24
6+9+10=27
6+8+11=27
6+7+11=24
7+8+9= 24
8+9+10=27
7+9+11=27 .........
We have 11 elements
We need a combination of 3
The combinations can be in the form
even+ even+ odd
odd+odd+odd
even + odd+odd
So there are 3 ways in which these elements can occur
Total number of combinations with 3 elements =11C3= 165
There are 6 odd numbers and 5 even numbers.
Number of subsets with 3 odd numbers = 6C3= 20
Number of two even numbers and 1 odd number = 5C2*6C1=10*6= 60
Number of 2 odd and 1 even number = 6C2* 5C1= 5*15= 75
So 20+60+75=155
There are 155 ways in which this combination can occur
Answer:
The correct locations are;
Part to part ratio is 3 cats to 5 dogs
Whole to part ratio is 10 pets to 2 rabbits
Part to whole ratio is 5 dogs to 10 pets
Step-by-step explanation:
The given information are;
The number of cats Jim has = 3
The number of dogs Jim has = 5
The number of rabbit Jim has = 2
The total number of pets Jim has = 3 + 5 + 2 = 10 pets
Therefore;
The fraction of the pets that are cats = 3/10
The fraction of the pets that are dogs = 5/10
The fraction of the pets that are rabbits= 2/10
Therefore we have;
Part to part ratio = 3/10 cats to 5/10 dogs = 3 cats to 5 dogs
Whole to part ratio → 10 pets to 2 rabbits
Part to whole ratio → 5 dogs to 10 pets.
