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2 years ago

Please help me with this question is 8 grade question

Mathematics

2 answers:

Rzqust [24]2 years ago

7 0

Answer:

a, -4.5

Step-by-step explanation: I should now I am in 10th grade math

mars1129 [50]2 years ago

4 0

Answer:

virign

Step-by-step explanation:

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For what values of x is the quantity x-7

Andreas93 [3]

positive = greater than 0.

Therefore we have the inequality:

$x-7 > 0$ |add 7 to both sides

$x > 7$

7 0

3 years ago

Write an equation of the line perpendicular to the given line that contains P.

lara31 [8.8K]

Answer:

Step-by-step explanation:

perp. -5

y + 7 = -5(x - 4)

y + 7 = -5x + 20

y = -5x + 13

7 0

3 years ago

The perimeter of a rectangle is 34 units. Its width is 6.5 point, 5 units.

12345 [234]

<h3><u>Question:</u></h3>

The perimeter of a rectangle is 34 units. Its width W is 6.5 units.

Write an equation to represent the perimeter in terms of the length L, and find the value of L

<h3><u>Answer:</u></h3>

The length of rectangle is 10.5 units

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangle = 34 units

Width of rectangle = 6.5 units

Let "L" be the length of rectangle

<em><u>The perimeter of rectangle is given by formula:</u></em>

Perimeter = 2(length + width)

<em><u>Substituting the values we get,</u></em>

$34 = 2(L + 6.5)$

Thus the equation is found

<em><u>Solve for "L"</u></em>

$L + 6.5 = \frac{34}{2}\\\\L + 6.5 = 17\\\\L = 17 - 6.5\\\\L =10.5$

Thus length of rectangle is 10.5 units

6 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Please help with this!!! Im so confused, I will mark brainliest if right!! Explain

devlian [24]

Answer: Yes these triangles are similar

Step-by-step explanation:

First lets write down what we know just to make life easier

x=9

TL should be similar to CH

LY should be similar to KH

The angles should be equal due to SAS

So the first thing we know is true is the fact that they have equal angles. Now we have to find out if the sides are similar or if they change by the same ratio to the other. If TL is similar to CH and TL=25 and CH=10 what is the change in size or dilation. Division should do the trick so 25/10=2.5 so TY is greater than CH by a factor of 10. Which means that LY should also be greater than KH by a factor of 2.5. If we are told that x=9 than side LY or 4(9)-1=35 and KH 9+5=14

So side KH is 14 and LY is 35. Now to check if they are similar then KH should be greater by a factor of 2.5. If this is not true than the sides are not similar. 35/2.5=14

Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5

Hope this helps.

8 0

3 years ago

Please help me with this question is 8 grade question​

Please help me with this question is 8 grade question