What is 128 fl oz converted to ??? Pint

1 answer:

5 0

1 oz=<span>0.12503671065 cup or about 0.13 cups

2 cups is 1 pint
1 oz=0.13/2=0.065

so 128 oz=
128 times 0.065=8.32 pints
</span>

You might be interested in

Find the sum (6x2+8x+8)+(12x3-12x2-2x)

Maslowich

The sum is 12x3+18x2-10x+8

7 0

3 years ago

One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t

Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

$M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}$

And if we replace the values given we have:

$M = \frac{8*4 + 16*4}{4+4}= 12$

b) $M = \frac{8*3 + 16*5}{3+5}= 13$

c) $M = \frac{8*5 + 16*3}{5+3}= 11$

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

$M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}$

And if we replace the values given we have:

$M = \frac{8*4 + 16*4}{4+4}= 12$

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

$M = \frac{8*3 + 16*5}{3+5}= 13$

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

$M = \frac{8*5 + 16*3}{5+3}= 11$

7 0

3 years ago

Convert 2 5/6 to an improper fraction

bearhunter [10]

Multiply the denominator by the number in front of it and then add it to the numerator. (6•2=12+5=17). The denominator stays the same. Your answer is 17/6. Hope this helped!

3 0

3 years ago

Slove -4(x+1)-3=(x-4)

Nastasia [14]

Answer:

$x=-\frac{3}{5}$