The ticket price that would maximize the total revenue would be $ 23.
Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:
- 20,000 x 30 + 20,000 x 8 = 760,000
- 24,000 x 25 + 24,000 x 8 = 792,000
- 28,000 x 20 + 28,000 x 8 = 784,000
- 26,000 x 22.5 + 26,000 x 8 = 793,000
- 27,200 x 21 + 27,200 x 8 = 788,000
- 26,400 x 22 + 26,400 x 8 = 792,000
- 25,600 x 23 + 25,600 x 8 = 793,600
- 24,800 x 24 + 24,600 x 8 = 792,000
Therefore, the ticket price that would maximize the total revenue would be $ 23.
Learn more in brainly.com/question/7271015
50.057 = 50.06 <span>to the nearest hundredth.</span>
Answer:
The entire floor can contain approximately 4178 fans
Step-by-step explanation:
The first step is to calculate the area of the basketball floor.
we can do this by multiplying the length by the breadth as such 94 X 50 = 4700 square feet.
The second step is to calculate the area occupied by 8 of the fans. We can do this by multiplying 3 ft by 3ft = 9 square feet.
From this, it will be easier to estimate the area occupied by only one fan. This can be got by dividing 9 square feet by 8.
This is = 1.125 square feet.
To get the number of students it can occupy, we divide the total area of the court by the area occupied by one student.
4700/ 1.125 =4177.8
4178 fans