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IRISSAK [1]
3 years ago
8

-8.5÷3.4 how to solve this step by step

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0
You have to move both decimals over and then divide. So the answer is 25.

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Point Q' is the image of Q(-7, -6) under the translation (x, y) + (x + 12, y + 8).
Lina20 [59]

Answer:

The co-ordinates of Q' is (5,2).

Step-by-step explanation:

Given:

Pre-image point

Q(-7,-6)

To find Image point Q' after following translation.

(x,y)\rightarrow (x+12,y+8)

Solution:

Translation rules:

Horizontal shift:

(x,y)\rightarrow (x+k,y)

when K>0 the point is translated k units to the right.

when K the point is translated k units to the left.

Vertical shift:

(x,y)\rightarrow (x,y+k)

when K>0 the point is translated k units up.

when K the point is translated k units down.

Given translation (x,y)\rightarrow (x+12,y+8) shows the point is shifted 12 units to the right and 8 units up.

The point Q' can be given as:

Q'=(-7+12,-6+8)=(5,2)

So, the co-ordinates of Q' is (5,2). (Answer)

7 0
3 years ago
The graph of an exponential function y=ab^x, if 0 0 and x&gt;0.<br> True or False?
emmasim [6.3K]

Im going to say falseStep-by-step explanation:

4 0
3 years ago
Read 2 more answers
The diameter of the inscribed circle in a regular hexagon is 4√3 inches long. What is the perimeter of this regular hexagon?
barxatty [35]

Answer:

12√3 inches or 20.785 inches.

Step-by-step explanation:

A regular hexagon can be defined as a polygon with 6 sides.

The formula for the perimeter of a regular hexagon =

6 × the length of the sides of the hexagon.

From the above question, we are told that there is an inscribed circle I'm the hexagon with a diameter of 4√3 inches long

Step 1

Find the radius of the circle

Radius of the circle = 4√3/2 = 2√3 inches

Step 2

The radius of the inscribed circle = Length of one of the sides of a regular hexagon.

Hence, the perimeter of the regular hexagon = 6 × 2√3

= 12√3 inches

= 20.784609691 inches.

Approximately 20.785 inches

3 0
2 years ago
Help me , i need fast​
MAVERICK [17]
I have a feeling it B but I don’t know maybe C
7 0
2 years ago
How much force is needed to accelerate a 2,500 kg car at a rate of 4 m/s
docker41 [41]
Force is equal to mass times acceleration.

So to find how much force is needed do 2,500 x 4, which equals 10,000.

Force is measure in Neutons so the answer will be:

10,000N of force is needed to accelerate a 2,500 car 4 m/s.
7 0
3 years ago
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