Answer:
value if a =

Step-by-step explanation:
here's the solution :-
=》
![\frac{ 2(\sqrt{m}) {}^{3} }{ \sqrt[4]{m} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%202%28%5Csqrt%7Bm%7D%29%20%20%7B%7D%5E%7B3%7D%20%7D%7B%20%5Csqrt%5B4%5D%7Bm%7D%20%7D%20)
=》

=》

=》

=》

=》

so, a = 5/4
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
The answer to your question is 113.04 in²
Step-by-step explanation:
To solve this problem substitute the values in the formula and simplify.
Data
Area = ?
radius = 6 in
π = 3.14
Formula
Area = π x r²
Substitution
Area = (3.14) x (6)²
Simplification
Area = 3.14 x 36
Result
Area = 113.04 in²
Answer:
-10y + 11.4
I hope this helps you out
<span>For more difficult cases, it may be easier to draw the graph first using the domain if possible and then determine the range graphically.See if you can find the inverse function. The domain of a function's inverse function is equal to that function's range.<span>Check to see if the function repeats.</span></span>