Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
<h3>
Inscribing a square</h3>
The steps involved in inscribing a square in a circle include;
- A diameter of the circle is drawn.
- A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
- The resulting four points on the circle are the vertices of the inscribed square.
Alicia deductions were;
Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle
Benjamin's deductions;
The diameters must be perpendicular to each other. Then connect the points, in order, around the circle
Caleb's deduction;
No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.
It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.
Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
Learn more about an inscribed square here:
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Answer:
F(-2)=-2²+3(-2)-2=4+-6×-2=4+12=16
The answer is b
Because you have to add da x and dat is 2x den add da numbers which is 4
Assuming Mark wants to buy a PS5 for $499.00 and the tax in her local county is 7.75% of the total sale, what will be the final cost is $538
Using this formula
Final cost =Total sales+ (Total sales×Tax)
Let plug in the formula
Final cost= $499.00+($499.00×7.75%)
Final cost= $499.00+$38.67
Final cost= $537.67
Final cost= $538 (Approximately)
Inconclusion Assuming Mark wants to buy a PS5 for $499.00 and the tax in her local county is 7.75% of the total sale, what will be the final cost is $538
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The formula for probability is # of favorable outcomes divided by the total number of outcomes.
So we know that there are a total of 5 letters. The child writes two letters, so we will have x/5 * x/5. Now, it is asking, what is the probability that they are both vowels.
We can see that a, i, and e are vowels, so the probability if the child were to write one letter would be 3/5. Since he is writing 2, you can multiply 3/5 * 3/5, which would give you your answer, 9/25. Therefore the probability that both letters are vowels is 9/25.
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