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kompoz [17]
3 years ago
11

Simplify 5 to the negative 4th power over 5 to the 3rd. Group of answer choices 57 5−1 1 over 5 1 over 5 to the 7th power

Mathematics
1 answer:
STatiana [176]3 years ago
5 0
When you divide exponents, you have to subtract them. So -4-3= -7 as the exponent

When you have a negative exponent, then you have to flip the fraction (all whole numbers are over 1 so flip the 1 to the top and the 5^7 on the bottom)

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Leah makes an origami photo frame to showcase her favorite family picture. The size
Andreyy89

Answer:

28 feet

Step-by-step explanation:

3.5 x 8 = 28

trust me

6 0
3 years ago
Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0
skad [1K]
\bf x^2+y^2-6y-8=0\qquad &#10;\begin{cases}&#10;x^2+y^2=r^2\\\\&#10;y=rsin(\theta)&#10;\end{cases}\implies r^2-6rsin(\theta)=8&#10;\\\\\\&#10;\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8&#10;\\\\\\\&#10;[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby &#10;\begin{array}{llll}&#10;\textit{so we need a value there to make}\\&#10;\textit{a perfect square trinomial}&#10;\end{array}

\bf 6rsin(\theta)\iff 2\cdot r\cdot  \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}&#10;\\\\\\&#10;\textit{now, bear in mind we're just borrowing from zero, 0}&#10;\\\\&#10;\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}

\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\&#10;\left. \qquad  \right.\uparrow \\&#10;\textit{so-called "completing the square"}&#10;\\\\\\\&#10;[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)&#10;\\\\\\&#10;r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)
3 0
3 years ago
Find the reference angle for 105 degree angle.
m_a_m_a [10]

Answer:

75° degree angle

Step-by-step explanation:

Since the angle 105° is in the second quadrant, subtract 105° from 180° .

180-105=75

6 0
3 years ago
Read 2 more answers
Can you please explain how you got the answer? Also plz tell me what the closed and open circle mean again..
ale4655 [162]

Answer: A

Step-by-step explanation:

  • Open circle means that x does not equal that number. For example, the open circle on C is on 8, so that shows x is not equal to 8.
  • Closed circle means that x does equal that number. For example on A, there is a closed circle on 8, so x could equal 8.

First, we need to solve the equation.

  1. Subtract 200 frim 1200 -> 125x ≥ 1000.
  2. Divide 125 from 1000 to isolate the x -> x ≥ 8

So, that means x is bigger than or equal to 8.

8 0
3 years ago
Read 2 more answers
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
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