<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Answer:
Step-by-step explanation:
It's algebra really, basically make a system of equations.
1b+5j=t
3b+2j=2t
I'm gonna solve the first one for buckets so we have it in terms of jars.
b+5j=t
b=t-5j
Now I plug that into the other equation
3b+2j=2t
3(t-5j)+2j=2t
3t-15j+2j=2t
Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other. or it other words solve for t.
3t-15j+2j=2t
3t-13j = 2t
3t = 2t+13j
t = 13j
So it takes 13 jars to make one tub, or one jar is 1/13 of a tub. You could then plug that in to one of the equations and find how much a bucket is.
Answer:
No,
Step-by-step explanation:
No, it's irrational.
Because, it is a non-terminating non recurring type number.
Answer:
d = 16.5
Step-by-step explanation:
Add -35.5 to both sides of the equation, then simplify.
... d + 35.5 - 35.5 = 52 - 35.5
... d + 0 = 16.5
... d = 16.5
_____
In general, if something unwanted is added, adding the opposite will undo that operation.
Answer:
Step-by-step explanation:
how does the graph look like
