Add 2p² to each side of the equation. Then you have
2p² + 16p + 24 = 0 .
Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by 2 . Then you have:
p² + 8p + 12 = 0 .
Now you have a nice, comfortable, familiar-looking quadratic equation.
You can either factor the left side into (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.
That's how to solve it, and find its two solutions.
F(-1)= -3 is (-1,-3) and f(2) = 6 is (2,6) where f(x) = y
y=mx + b is the slope-intercept form whereas m equals the slope (rate of change) and b equals the y-intercept (initial amount/what y is when x is 0.)
First, we need to find the slope between the two points (-1,-3) and (2,6). To find the slope we could use one of it's formulas

.
1. (-1,-3)
2. (2,6)

→

→

The slope is 3 (

). Thusly, y = 3x + b
To find out the y-intercept, we can reverse the slope. [Note: This

is in

where rise is 'y' and run is 'x'. Reversed would be

]. Take the second ordered pair and use our reversed slope on it until we get 0 for x.
(2, 6) ⇒ (2 - 1, 6 -3) ⇒ (1, 3) ⇒ (0,0)
Y-intercept is 0. Therefore,
y= 3x + 0 [NOTE: y = f(x), so if you want it in function notation form it's just f(x) = 3x + 0.]
Joanna would have spent $8.94 on apples at the farmers market.
Answer:
Step-by-step explanation:
Alright, lets get started.
Lets find slope for both bikes one by one
For bike 1 :
There are two points on the graph of Bike 1, these two points are (2,3) and (4,6)
So the slope for bike 1 is : 
So the slope for bike 1 is : 
So the slope for bike 1 is : 
For bike 2 :
There are two points on the graph of Bike 2, these two points are (4,5) and (8,10)
So the slope for bike 2 is : 
So the slope for bike 2 is : 
Hence Bike 1 will win the race as slope of line bike1 is greater than slope of line bike 2. So, answer is option D