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3 years ago

Choose an inverse function and use SohCahToa to find angle A.

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

6 0

Answer:

$m\angle A=53.13^o$

Step-by-step explanation:

we know that

In the right triangle of the figure

The cosine of angle A is equal to divide the adjacent side to angle A by the hypotenuse

$cos(A)=\frac{6}{10}$ ----> by CAH

Find the measure of the angle A

$m\angle A=cos^{-1}(\frac{6}{10})$

$m\angle A=53.13^o$

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Please help 10 points

KIM [24]

Answer:

SAS triangle because a SAS stands for side angle side that's how u always know

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2 years ago

How many solutions can be found for the equation 3x − 2 = 3x + 5?

aksik [14]

Answer:

Zero

Step-by-step explanation:

there is no solution the sides are uneven. if you solve for it 3x and 3x cancels out each other leaving you with -2=5

7 0

3 years ago

Read 2 more answers

The lengths of the two sides of a triangle (not necessarily a right triangle) are 1.00 meters and 3.46 meters. The sine of the a

Hoochie [10]

Answer:

0.1228

Step-by-step explanation:

We use sine rule

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

where, in any triangle ABC, a is the side opposite ∠A, b is the side opposite ∠B and c is the side opposite ∠C.

Applying this to the question,

$\dfrac{1.00}{0.0355} = \dfrac{3.46}{\sin B}$

$\sin B = 3.46\times0.0355 = 0.12283 \approx 0.1228$

7 0

3 years ago

The amount of polonium-210 remaining, p(t), after t days in a sample can be modeled by the exponential function p(t) = 100e−0.00

Archy [21]

Answer:

% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g

Step-by-step explanation:

p(t) = 100e^(-0.005t)

Initial amount: p(0) = 100

Amount remaining: p(t) = 100e^(-0.005t)

Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]

% of Po lost = amount lost/initial amount × 100 %

= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %

p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g

The mass of polonium remaining after 63 days is 73 g.

4 0

2 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

Addition:

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

Multiplication:

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

3 years ago