For one roll, you need to take that 1/3 cup and split it into 5 parts. To do this, divide by 5, which means the fraction becomes 1/15, giving you 1/15 cup flower for one roll.
36 rolls is just 36 times the one roll, which is 36/15 cups. You can divide both parts by 3 to make that 12/5 cups for 36 rolls.
The correct answer is: [D]: " 7.2 units" .
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Explanation:
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Use the Pythagorean theorem:
a² + b² = c² ;
in which: "6 units" and "4 units" equal the lengths of the right angle (formed by the rectangle); and "c" is the length of the diagonal of the rectangle, or the "hypotenuse", of the right triangle formed by the rectangle; We wish to solve for "c" ;
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6² + 4² = c² ; Solve for "c" ;
↔ c² = 6² + 4² ;
= (6*6) + (4*4) ;
= 36 + 16 ;
= 52 ;
c² = 52 ;
Take the "positive square root" of each side of the equation; to isolate "c" on one side of the equation; and to solve for "c" ;
√(c²) = √52 ;
c = √52 ;
At this point, we know the 7² = 49 ; 8² = 64 ; so, the answer is somewhere between "7" and "8" ; yet closer to "7" ; so among the answer choices given;
The correct answer is: [D]: " 7.2 units" .
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However, let use a calculator:
c = √52 = 7.2111025509279786 ; which rounds to "7.2" ;
which corresponds to:
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Answer choice: [C]: " 7.2 units" .
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Answer:
5.66 units
Step-by-step explanation:
A's per our discussion, x is a leg of right triangle.
Therefore, by Pythagoras theorem:


Write a C program to compute Matrix Multiplication of two matrices. Use one dimensional array to store each matrix, where each row is stored after another. Hence, the size of the array will be a product of number of rows times number of columns of that matrix. Get number of row and column from user and use variable length array to initialize the size of the two matrices as well as the resultant matrix. Check whether the two matrices can be multiplied or not. Write a getMatrix() function to generate the array elements randomly. Write a printMatrix() function to print the 1D array elements in 2D Matrix format. Also, write another function product(), which multiplies the two matrices and stores in the resultant matrix. With SEED 5, the following output is generated.
Sample Output
Enter the rows and columns of Matrix A with space in between: 3 5
Enter the rows and columns of Matrix B with space in between: 5 4
Matrix A:
8 6 4 1 6
2 9 7 7 5
1 3 1 1 2
Matrix B:
9 5 4 5
9 9 8 1
4 4 3 5
2 6 2 1
4 5 2 4
Product AxB:
168 146 106 91
161 186 125 81
50 52 37 22
In conclusion, the answer is 5x1
Please give Brainliest answer thanks! :)
Since your slope is 3, (the number for slope is always right before x) and your y-intercept is one (that is always the number after the x) your answer would be B