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alexandr1967 [171]
3 years ago
12

drag and drop each expression to correctly classify if it as having a positive or negative product just put them in order from p

ositive to negative. WHOEVER GIVES ME THE RIGHT ANSWER I WILL MAKE BRAINLIEST

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

The two in the middle are the negatives and the two that are on the sides are positive.

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Determine the direction that this parabola opens y=x^2-6x
nalin [4]

Answer:

the graph of the parabola opens upwards.

Step-by-step explanation:

For any quadratic equation of the form

ax ^ 2 + bx + c is true that:

if the main coefficient "a" is negative then the graph of the parabola opens downwards.

If the main coefficient "a" is positive, the parabola opens upwards

In this case the parabola is y=x^2-6x

Note that a=1 and a>0 therefore the graph of the parabola opens upwards.

8 0
3 years ago
3x + 4y = 8<br> How do I solve this
dimaraw [331]

Answer:

y= (-3x+8)/4

x = (-4 +8)/3

Step-by-step explanation:

3x + 4y = 8

-3x               -3x

4y = -3x +8     divide ALL by 4

y= (-3x+8)/4

3x + 4y = 8

    -4y          -4y

3x = -4 +8     divide ALL by 3

x = (-4 +8)/3

5 0
3 years ago
A loan if 12 000 was borrowed from a bank at 14% per annum calculate the total amount owning at the first year​
Advocard [28]

Answer: P = $ 12000

r = 14%

t = 1 (for first year)

I = (P X r X t)/100

∴ I = (12000 X 14 X 1)/100

   = 120 X 14

   = $ 1680   <---------- (Interest on loan at the end of first year)

∴ Total amount owing at the end of first year = (P + I)

                                                                          = (12000 + 1680)

                                                                          =  $ 13680

Repayment = $ 7800

Amount still outstanding (at the start of second year) = 13680 - 7800

                                                                                       =  $ 5880

Interest on the outstanding amount at the end of second year,

P (new) = $ 5880

r (same) = 14%

t = 1 (for the current second year)

∴ I = (P X r X t)/100

   = (5880 X 14 X 1)/100

   = 82320 / 100

   = $ 823.2   <-------------------------- (Interest on outstanding amount at the end of second year)

7 0
3 years ago
In the school band, there are 5 trumpet players and f flute players. There are twice as many flute players as there are trumpet
mestny [16]

Answer:

Which of the following is the scaling factor a of the function f(x) = 3|x|?

Step-by-step explanation:


4 0
3 years ago
Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°
Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

\angle OQR+\angle ORQ+\angle ROQ=180^o

Now, since the figure already shows that angle m\angle2+\angle ORQ+50^o=180^oNow, since we have established that the base angles m\angle2+m\angle2+50^o=180^owe can now solve the above equation for m<2 as follows:

\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}

Therefore, the correct answer is: option D

7 0
1 year ago
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