2 years ago

Find the area of a triangle given that c=40m b=20m a=48°

1 answer:

8 0

$Area= \frac{1}{2}\cdot c\cdot b\cdot sin \alpha \\\\------------------\\\\A= \frac{1}{2}\cdot 40\cdot20\cdot sin48^0\approx400\cdot0.7431=297.24\ [m^2]\\\\Ans.\ Area\ is\ about\ 297.24\ [m^2]$

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