If 101 use 3/5 for his Artwork, then the space remaining for 102 is:
5/5 - 3/5 = 2/5 (since the whole wall represents 100% or 5/5 or 1)
The nswer is c 30 degres hop i helped :p
Answer
Find out the area of the running track that goes around the field .
To proof
Formula
Area of rectangle = length× breadth
![Area\ of\ semi-circle = \frac{1}{2}\pi r^{2}](https://tex.z-dn.net/?f=Area%5C%20of%5C%20semi-circle%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r%5E%7B2%7D)
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
area of running track = outside area - inside area
First case ( outside )
length = 73 + 2 × 9.76
= 92.52m
Breadth = 84.39 m
radius of outside semi circle
![= \frac{92.52}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B92.52%7D%7B2%7D)
=46.26m
outside area = area of rectangle + 2× area of the semi- circle
= 92.52× 84.39 + 3.14× 46.26 ×46.26
= 7807.76+ 6719.56
= 14527.32 m² ( approx)
Second case
radius of the semi- circle
![= \frac{73}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B73%7D%7B2%7D)
=36.5m
inside area = area of rectangle + 2× area of the semi- circle
= 73× 84.39 + 3.14× 36.5 ×36.5
= 6160.47 + 4183.27
= 10343.74m²
area of running track= 14527.32 m² - 10343.74m²
= 4183.58m²
Hence proved
Answer:
Answer: 36,000 would be 20 percent. 72,000 would be 40 percent. Step-by-step explanation: You just divide 36,000 by 180,000