C₆H₁₂O₆ + 6 O₂ ⇒ 6 CO₂ + 6 H₂O
This is an oxidation-reduction reaction, because oxidation numbers of carbon and oxygen atoms are different than before reaction.
(-_-(-_-)-_-)
This law (expressed mathematically as E = σT4) states that each gadget with temperatures above absolute zero (0K or -273°C or -459°F) emits radiation at a charge proportional to the fourth energy in their absolute temperature.
Wien's displacement law states that the black body radiation curve for one-of-a-kind temperatures height at a wavelength is inversely proportional to temperature.
Wien's displacement law It states that the better the temperature, the lower the wavelength λmax for which the radiation curve reaches its most. The shift to shorter wavelengths corresponds to photons of better energies. In other phrases, λmax (height wavelength) is inversely proportional to temperature.
Wien's regulation, named after the German Physicist Wilhelm Wien, tells us that gadgets of different temperatures emit spectra that height at distinctive wavelengths. hotter objects emit radiations of shorter wavelengths and for this reason, they seem blue.
Wien's regulation tells us that gadgets of various temperatures emit spectra that top at specific wavelengths. hotter gadgets emit a maximum of their radiation at shorter wavelengths; subsequently, they will seem like bluer. Cooler gadgets emit most of their radiation at longer wavelengths; consequently, they'll appear redder.
Learn more about Wien's law here: brainly.com/question/13380837
#SPJ4
Answer:
D will brain cancer eventually be curable?
Explanation:
Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.