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lara31 [8.8K]
3 years ago
15

What is the answer??

Chemistry
1 answer:
Nata [24]3 years ago
8 0
Compounds have "different" properties than the elements they are composed of.
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X^2/2x^5=2<br><br>how do you solve this ?
Natasha2012 [34]

Answer:

x=\sqrt[3]{\frac{1}{4}}

Explanation:

\displaystyle\frac{x^2}{2x^5}=2\\\\x^2=4x^5\\\\1=4x^3\\\\x^3=\frac{1}{4}\\\\\\x=\sqrt[3]{\frac{1}{4}}

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2 years ago
What is the scientific name for weight?
katovenus [111]

Hello the term for weight is newton

hope this helped.

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5 0
3 years ago
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What do the conclusions tell about the experiments?
Anni [7]

Answer:

the answer would be C of not C is B

4 0
2 years ago
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What can you summarize about the use of acid-base indicators?
densk [106]

An acid-base indicator is used to identify the presence of an acid or base. These indicators exhibit different colors depending on the solution that they are in. They are especially useful when completing titrations to determine the molarity of an unknown substance and is denoted as option D.

<h3>What is Titration?</h3>

This is done in the laboratory and involves the slow addition of one solution of a known concentration to a known volume of another solution of unknown concentration.

Acid-base indicators are used to determine the presence of an acid or base in a solution which is based on the colors seen when performing the chemical reaction.

It is used to calculate the the molarity of an unknown substance through the knowledge of the other parameters which is therefore the reason why option D was chosen as the most appropriate choice.

Read more Acid-base indicators  here brainly.com/question/2815636

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6 0
9 months ago
Find the volume of a gas if 3.6 mols of the gas is at STP
Digiron [165]

Answer:

81 L gas

General Formulas and Concepts:

<u>Ideal Gas Law</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.6 mols gas at STP

[Solve] volume (L) of gas

<u>Step 2: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.6 \ mol \ gas(\frac{22.4 \ L \ gas}{1 \ mol \ gas \ at \ STP})
  2. [DA] Multiply [Cancel out units]:                                                                      \displaystyle 80.64 \ L \ gas

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

80.64 L gas ≈ 81 L gas

6 0
3 years ago
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