There are 2071.4662 grams of glucose in 11.5 moles.
Per 1 mole there are 180.15588 grams of glucose. 180.5588 x 11.5 =2076.4262
 
        
             
        
        
        
X will be hydronium (H3O)
        
                    
             
        
        
        
Tetraamminedichloridoiron(3) nitrate
 
        
             
        
        
        
The  number  of  potassium  atom  that  are  in  0.25  moles   potassium  carbonate  is  calculated  as  follows
by  use  of Avogadro  contant
1  mole=  6.02  x10^23   atoms
what  about  0.25 moles,   
by  close  multiplication
{0.250 moles  x 6.02  x10^23}  /  1 mole  =  1.505  x10^23  atoms