1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
S_A_V [24]
3 years ago
6

Why are the carboxylic acid groups of the amino acids so much more acidic (pka~ 2) than a carboxylic acid such as acetic acid (p

ka=4.76)?
Chemistry
1 answer:
qwelly [4]3 years ago
6 0
<span>The groups you mention are withdrawing electrons with inductive effect. Because there is no conjugation between the acids (pk-2 and pka 4.76), nitrogen makes it impossible to bind to the carboxyl group. Acids are affected in two ways, the first since the electron subtraction of charged oxygen molecules, and the second way by polarizing the O-H bond with carboxylic acid, this helps the protons to split easily.</span>
You might be interested in
1. Why<br> are atoms considered the building blocks of life?
Fed [463]

Answer:

Explanation:

Atoms are the basic building blocks of ordinary matter. Atoms can join together to form molecules, which in turn form most of the objects around you. ... A particular atom will have the same number of protons and electrons and most atoms have at least as many neutrons as protons.

6 0
3 years ago
Read 2 more answers
What is the relationship between the amount of sugar added and the amount of CO2 gas produced?
Marina CMI [18]
B.If more sugar is added,more carbon dioxide gas is produced,making the ballon larger
8 0
3 years ago
Which structure is responsible for producing pollen in flowering plants?
nekit [7.7K]

Answer:

The stamen!

The stamen is often made up of anthers and filaments

6 0
3 years ago
An oxygen (O2) molecule is adsorbed on a patch of surface (see sketch at right). This patch is known to contain 324 adsorption s
julia-pushkina [17]

The change in entropy is 2.91 x 10-24 J/K

For an ideal gas,

The entropy of a molecule, S = KB ln(W)

KB – Boltzmann constant (1.38065 x 10-23 J/K)

W – Equivalent microstates of the molecule.

Winitial = 324

Wfinal = 400

Sfinal – Sinital = KB ln(Wfinal) - KB ln(Winital)

ΔS = KB ln(Wfinal / Winital)

= (1.38065 x 10-23 J/K) * ln(400/324)

= 2.91 x 10-24 J/K

In the ideal gas law, the temperature of the hydrogen gas is determined if the volume and pressure of the gas are known.

Learn more about ideal gas here: brainly.com/question/25290815

#SPJ4

4 0
1 year ago
What part of your body help grow to Detect and respond to changes in your environment?
Kitty [74]
Your nerves.
Hope it helps!

6 0
3 years ago
Read 2 more answers
Other questions:
  • Calculate the mole fraction of total ions in an aqueous solution prepared by dissolving 0.400 moles of mgcl2 in 850.0 g of water
    8·1 answer
  • When magnesium carbonate, mgco2, reacts with nitric acid, hno3, magnesium nitrate and carbonic acid form. carbonic acid then bre
    9·2 answers
  • Magnesium has three stable isotopes. One has 12 neutrons the second has 13 and the third has 14. Which one is the most abundant?
    9·1 answer
  • What is the outer electron configuration for tin
    6·1 answer
  • Which of the following is the best reference for more information regarding compounding?
    13·1 answer
  • When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
    7·1 answer
  • A local barista serves coffee at 85°C. You add ice to the coffee to cool it to 55°C. Assume that an ice cube is 24 g and -18.5°C
    8·1 answer
  • concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature
    13·1 answer
  • You are pushing a refrigerator of 150 kg with a force of 50 Newtons. By how
    5·1 answer
  • Describe how the properties of elements in the same group differ to the properties of elements in the same period
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!