√8+√18−√32
√2^2·2+√3^2·2−√2^4·2
√2^ 2·√2+√3^2·√2−√2^4·√2
√2 is the answer
First write out all the two digit square numbers
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
Next divide all of them by 7
16/7 = 2 2/7 or 2 and 2 remainders
25/7 = 3 4/7 or 3 and 4 remainders
36/7 = 5 1/7 or 5 and 1 remainder
49/7 = 7
64/7 = 9 1/7 or 9 and 1 remainder
81/7 = 11 4/7 or 11 and 4 remainders
This tells us that the only possible remainders for a two digit square number divided by 7 are 1, 2 and 4
If Doris got 6 and Horace got 3, they must have made a mistake.
Answer:
-4 83/100 8 3/10
Step-by-step explanation:
The correct answer to this would be -3x+8
