I need help with this problem

Mathematics

1 answer:

kolbaska11 [484]2 years ago

7 0

It’s 20 I believe. All together it should be 160 so you add 118 and 22 to get 140. Then subtract that from 160 and you get 20.

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Sketch the graph: y=1/3x+2

Cerrena [4.2K]

The slope of the line is 1/3and the y-intercept is at the (0, 2) as shown in the graph below.

<h3>Graph of a linear function</h3>

A linear function is a function that has a leading degree of 1. The standard equation for a linear function is expressed as:

y = mx + b

where

m is the slope which is equal to the rate of change of y coordinate to x-coordinates.

b is the y-intercept

Given the following equation

y= 1/3x + 2

The slope of the line is 1/3 and the y-intercept is at the(0,2) as shown in the graph below.

Learn more on equation of a line here: brainly.com/question/13763238

#SPJ1

6 0

1 year ago

Can you please answer this question

tamaranim1 [39]

$3tan^{2} \theta +7sec\theta=3$
First I converted the equation terms into sine and cosine.
$tan^{2}\theta = \frac{sin^{2}\theta}{cos^{2}\theta}$ and $sec\theta= \frac{1}{cos\theta}$
Substitution:
$\frac{3sin^2\theta}{cos^2\theta} + \frac{7}{cos\theta} =3$
Common Denominator Created:
$\frac{3sin^2\theta}{cos^2\theta} + \frac{7cos\theta}{cos^2\theta} =3$
Multiply each term by the LCD:
$3sin^2\theta+7cos\theta=3cos^2\theta$
Substitution: Recall ⇒ $sin^2\theta =1-cos^2\theta$
$3(1-cos^2\theta)+7cos\theta=3cos^2\theta$
Distribute and collect all terms on one side:
$6cos^2\theta-7cos\theta-3=0$
Factor and set each factor equal to 0:
$(2cos\theta-3)(3cos\theta+1)=0$
$2cos\theta-3=0$ ⇒ $theta=cos^{-1} \frac{3}{2}$
$3cos\theta+1=0$ ⇒ $theta=cos^{-1} \frac{-1}{3}$
The 2nd factor provides only possible answer 109.5 degrees

4 0

3 years ago

I need help pleaseeee!!!!! I don’t understand

olganol [36]

Answer:

a. x = 5, m∠FGH = 22°

b. m∠HGI = 22°

c. m∠FGI = 44°

Step-by-step explanation:

Since GH bisects FGI this means it divides the angle in two equal parts.

a. solving for x means equating them:

5x-3 = 6x-8 =>