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4 years ago

What does the law of demand state?

Mathematics

2 answers:

Elodia [21]4 years ago

6 0

Answer:

B. is the correct answer

katrin2010 [14]4 years ago

4 0

The correct answer is B

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The mass of an ant is 1/10 of the load, which it can carry in one try. What is the mass of the ant, if in one time it can carry

Viefleur [7K]

If you call $m$ the mass of the ant and $l$ the load, we have the equation

$m = \cfrac{l}{10}$

In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.

Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:

$m = \cfrac{\frac{7}{250}}{10} = \cfrac{7}{250}\cdot\cfrac{1}{10} = \cfrac{7}{2500}$

8 0

4 years ago

A store has 7 red shirts, 15 black shirts, 13 white shirts, and 5 green shirts. Select the portion of the shirts that are black.

Svetach [21]

First you must add all of the shirts together, which gives you: 40

Since 15 of those are black, then you need to put those 15 over the total number of 40, making it 15/40.

Then you must simplify by the highest number that will go into both, and since that number is 5, it will then go into 15 three times and it will go into 40 eight times.

That leaves you with the answer of: 3/8

Hope I helped and good luck on your test! Please mark as brainliest if right? :)

4 0

3 years ago

What are the following values from least to greatest 0 6 1/2 -1 9 can you help me pleaseeee

alisha [4.7K]

-1, 0, 1/2, 6, 9 hope that helps

7 0

3 years ago

PLS HELP TIMED HW WILL GIVE BRAINLEIST

pochemuha

Answer:

4.8

Step-by-step explanation:

$V_{sphere} = \frac{4}{3} \pi r^3$

$144\pi= \frac{4}{3} \pi r^3$

$r^3 = \frac {3 \times 144\pi}{4\pi}$

$r^3 = 3 \times 36$

$r^3 = 108$

$r = \sqrt[3]{108} \\ \\ r = 4.7622031559 \\ \\ r \approx \: 4.8 \:$

4 0

3 years ago

Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t

alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

6 + 6 = 12 seeds, which means that $N = 12$

6 treated, which means that $k = 6$

Five sprouted, which means that $n = 5$

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076$

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0

3 years ago