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4 years ago

The square root of 9x^4/36 simplified

Mathematics

1 answer:

Serggg [28]4 years ago

6 0

Step-by-step explanation:

$\sqrt{ \frac{9 {x}^{4} }{36} } \\ \\ = \sqrt{ \frac{ {x}^{4} }{4} } \\ \\ = \frac{ {x}^{2} }{2}$

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Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and st

SashulF [63]

Answer:

0.7233

Step-by-step explanation:

We want to find the area between the z-scores z=-0.95 and z=1.25.

We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.

For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.

This gives P(z<-0.95)=0.1711

Similarly the area to the left of z=1.25 is

P(z<1.25)=0.8944

Now the area between the two z-scores is

P(-0.25<z<1.25)=0.8944-0.1711=0.7233

7 0

3 years ago

If f(x)=-3x-2, find f(-2)+9

mash [69]

Answer:

Step-by-step explanation:

Replace the variable x with -2 in the expression.

f (-2) = -3 x -2 -2

Simplify (-3 x -2 -2) + 9

Multiply -3 by -2

6 - 2 + 9

Subtract 2 from 6

4 + 9

add 4 and 9

13.

4 0

3 years ago

Use your calculator to work out this equation

alisha [4.7K]

Answer:

2.123842852 is the first answer

for part b it'll be 2.12

hope that helps

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago

Which point is the reflection of point E across the y-axis ? What’s are it’s coordinates?

andriy [413]

Answer:

I need more info

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers