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Savatey [412]
3 years ago
5

In Simpson's rule, why does the n (number of strips) have to be an even number?​

Mathematics
1 answer:
horsena [70]3 years ago
4 0

Answer:

This approach often yields much more accurate results than the trapezoidal rule does. Again we divide the area under the curve into n equal parts, but for this rule n must be an even number because we're estimating the areas of regions of width 2Δx.

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What is the fully factored form of the expression 45x²y2 + 18x3
Llana [10]

Answer:

9x^2(5y^2 + 2x).

Step-by-step explanation:

First find the Greatest Common Factor of the 2 terms.

GCF of 18 and 45 = 9

GCF of x^2 and x^3 = x^2.

The complete GCF is therefore 9x^2.

So, dividing each term by the GCF, we obtain:

9x^2(5y^2 + 2x).

4 0
3 years ago
Chandani purchased some parrots. 20% flew away and 5% died. Of the remaining, 45% were sold. Now 33 parrots remain. How many par
Paha777 [63]

Answer:

80 parrots were purchased.

Step-by-step explanation:

Let the total number of parrots be k.

If 20% (or 20/100 = 1/5) flew away and 5% (5/100 = 1/20) died, the remaining parrots will be k – (¹/₅k + ¹/₂₀k) = k – ¼k = ¾k.

Of the remaining, 45% (or 45/100 = 9/20) were sold, which means the total number of sold parrots will be ¾k × ⁹/₂₀ = ²⁷/₈₀k.

The remaining parrots = ¾k – ²⁷/₈₀k = ³³/₈₀k = 33

k = 33 × ⁸⁰/₃₃ = 80 parrots were purchased.

8 0
3 years ago
A teacher pays $39 for 10 books.What is the unit price of each book?
zheka24 [161]

To find the cost of each book, you need to divide the money spent on all of the books by the number of books.


$39 / 10 = $3.90 per book

8 0
4 years ago
Read 2 more answers
A furniture company has 480 board ft of teak wood and can sustain up to 450 hours of labor each week. Each chair produced requir
miskamm [114]

The numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.

Since a furniture company has 480 board ft of teak wood and can sustain up to 450 hours of labor each week, and each chair produced requires 8 ft of wood and 12 hours of labor, and each table requires 20 ft of wood and 15 hours of labor, to determine, if a chair yields a profit of $ 65 and a table yields a profit of $ 90, what are the numbers of chairs and tables that should be produced each week in order to maximize the company's profit, the following calculation should be done:

  • 16 chairs; 24 tables
  • Time used = 16 x 12 + 24 x 15 = 192 + 360 = 552
  • Wood used = 16 x 8 + 24 x 20 = 128 + 480 = 608  
  • 15 chairs; 18 tables
  • Time used = 15 x 12 + 18 x 15 = 180 + 270 = 450
  • Wood used = 15 x 8 + 18 x 20 = 120 + 360 = 480  
  • 12 chairs; 28 tables
  • Time used = 12 x 12 + 28 x 15 = 144 + 420 = 564
  • Wood used = 12 x 8 + 28 x 20 = 96 + 540 = 636  
  • 18 chairs; 20 tables
  • Time used = 18 x 12 + 20 x 15 = 216 + 300 = 516
  • Wood used = 18 x 8 + 20 x 20 = 144 + 400 = 544

Therefore, the only option that meets the requirements of time and wood used is that of 15 chairs and 18 tables, whose economic benefit will be the following:

  • 15 x 65 + 18 x 90 = X
  • 975 + 1,620 = X
  • 2,595 = X

Therefore, the numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.

Learn more in brainly.com/question/14728529

8 0
2 years ago
A sample size of n = 64 is drawn from a population whose standard deviation is o = 5.6.
AlekseyPX

Answer:

The margin of error for a 99% confidence interval for the population mean is 1.8025.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem:

\sigma = 5.6

So

M = 2.575*\frac{5.6}{\sqrt{64}} = 1.8025

The margin of error for a 99% confidence interval for the population mean is 1.8025.

5 0
3 years ago
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