Find the missing numbers in the equivalent fraction for 1/

Let n1equals50, Upper X 1equals30, n2equals50, and Upper X 2equals10. Complete parts (a) and (b) below. a. At the 0.05 leve

Viefleur [7K]

Answer:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

$z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082$

$p_v =2*P(Z>4.082)=4.46x10^{-5}$

So the p value is a very low value and using any significance level for example $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation

$X_{1}=30$ represent the number of people with a characteristic in 1

$X_{2}=10$ represent the number of people with a characteristic in 2

$n_{1}=50$ sample of 1 selected

$n_{2}=50$ sample of 2 selected

$p_{1}=\frac{30}{50}=0.6$ represent the proportion of people with a characteristic in 1

$p_{2}=\frac{10}{50}=0.2$ represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082$

4) Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a two sided test the p value would be:

$p_v =2*P(Z>4.082)=4.46x10^{-5}$

So the p value is a very low value and using any significance level for example $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

3 0

3 years ago

Anyone who know how to do this answer i will give you 20 Brainly points and mark the Braninllest person who get it right.

notka56 [123]

Answer:

Answer is A

Step-by-step explanation:

(14x^4y^6)/(7x^8y^2)

because everything is one term, you can split into three terms

14/7, x^4 / x^8 , and y^6/y^2

multiplying these three terms will get us the starting term

14/7 = 2

x^4 / x^8

with division of exponents, you subtract the smaller exponent (4), from the big exponent (8), and leave it on the same side (bottom) as the big exponent

1/x^4

same thing with our y's

y^6/y^2

this time, the term stays on the top

y^4

take the simplified terms and multiply them together

(2) * (1/x^4) * (y^4) =

A: (2y^4) / (x^4)

7 0

3 years ago

3 + 12 + 48 + 192 + ...<br> Whats the answer

Alex

The sequence is to take the previous number and multiply by 4, so the sequence is

3 12 48 192 768 3072 12288

add them all up and you get 16383

8 0

2 years ago

Read 2 more answers

Plz help w this math problem

Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

${ \tt{x = 2a \sqrt{t} }} \\ \\ { \tt{ \sqrt{t} = \frac{x}{2a} }} \\ \\ { \boxed{ \tt{t = \frac{ {x}^{2} }{4 {a}^{2} } }}}$

• then find y:

${ \tt{y = {ar}^{2} - 2at}} \\ \\ { \tt{y = {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\ \\ { \boxed{ \tt{y = {ar}^{2} - \frac{ {x}^{2} }{2a} }}}$

6 0

3 years ago

⎡⎣⎢⎢⎢⎢⎢⎢Scores4567Frequency1581310⎤⎦⎥⎥⎥⎥⎥⎥

V125BC [204]

Answer:

What is this Bro

<h2>Can you explain</h2>

6 0

3 years ago

Find the missing numbers in the equivalent fraction for 1/_ =2/18