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Shkiper50 [21]
3 years ago
11

Sally spins a fair spinner numbered 1 - 6 and flips a fair coin. What is the probability of obtaining a multiple of 3 and a tail

?
Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0
The probability is 1/6

The likelihood of Sally spinning a multiple of 3 is 2/6 (or 1/3).

The likelihood of her flipping a tail is 1/2.

To find the probability of two independent events, multiply said individual probabilities together.

(1/3)(1/2) = 1/6
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Step-by-step explanation:

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you and a friend tutor for a total of 12 hours. use the tape diagram to find how many hours you tutor. ​
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3 years ago
Keshav and Noel started to cycle together from Nehru Park. Keshav takes a break to drink water after (k hours), where k is the f
Oduvanchick [21]

Answer:

LCM (k, n) = 10 and HCF(k, n) = 2

Step-by-step explanation:

The given parameters are;

The time after which Keshav takes  a break = k hours

The value of k = The first smallest prime natural number

Therefore, by mathematical definition, k = 2

The time after which Noel takes a break = n hours

The value of n = The fifth smallest composite natural number

The first five composite numbers are given as follows;

4, 6, 8, 9, and 10

Therefore, the fifth smallest composite natural number = 10 = n

The LCM (k, n) = LCM (2, 10) = Least common multiple of 2 and 10 is given as follows;

Dividing by 2, we get;

2/2 = 1,  10/2 = 5

Dividing the result by 5, we get;

5/5 = 1

Multiplying the devisors together gives;

5 × 2 = 10

Therefore, the LCM of 2 and 10 = 10

LCM(2, 10) = LCM (k, n) = 10

The HCF(k, n) = HCF of 2 and 10 = The highest common factor that divides both 2 and 10 is given as follows;

Dividing 2 and 10 by 2 gives;

2/2 = 1 and 10/2 = 5

Therefore, HCF(k, n) = The highest common factor of 2 and 10 = HCF(2, 10) = 2

4 0
3 years ago
Find the largest positive integer that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively.​
marin [14]

Required number is 17.

<h3>Justification:</h3>

<u>We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively</u>.

Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).

Hence,

  • 398 - 7 = 391
  • 436 - 11 = 425
  • 542 - 15 = 527

Now, you can find the HCF(391, 425, 527) = 17

<u>Hence, the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17</u>.

8 0
2 years ago
Read 2 more answers
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