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Marina CMI [18]
3 years ago
9

15. Construct the slope-intercept form equation of the line passing through (-5,23) and (10,-5).

Mathematics
1 answer:
Radda [10]3 years ago
3 0

Answer:

15<em>y</em> = -28 <em>x</em> + 205.

Step-by-step explanation:

Slope intercept  form of equation is <em>y = mx + c</em> where m is slope and c is the y intercept.

Now slope of line passing through points (-5, 23) and (10, -5):

m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-5 -23}{10 + 5} = \frac{-28}{15}

Now equation of line:

<em> y = mx + c</em>

substituting the value of m in above expression,

y = -\frac{28}{15} x + c

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,

23 = -\frac{28}{15} \times (-5) + c

23 = \frac{28}{3} + c

c = 23 - \frac{28}{3} = \frac{69 - 28}{3} = \frac{41}{3}

So equation of line in slope intercept form:

y = -\frac{28}{15} x + \frac{41}{3}

Further solving,

15<em>y</em> = -28 <em>x</em> + 205.

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