Answer: A. Mean of sampling means 
Standard deviation of sampling means =
B. The probability that your sample has mean less than 165 is 0.1492 .
Given : The distribution of blood cholesterol level in the
population of young men aged 20 to 34 years is close to normal with
mean 
Mg/dl and standard deviation 
mg/dl.
Sample size : n= 150
Let 
sample mean values.
A. The mean and the standard deviation of the distribution of the sampling means would be :
Mean of sampling means =
Standard deviation of sampling means = 
The probability that your sample has mean less than 165 would be
Hence , the probability that your sample has mean less than 165 is 0.1492 .
33 * 1/4 = 8.25
22 * 1/4 = 5.5
x = 5.5
scale factor = 1/4
You can have a lot of ways to solve this problem, but I'm going for solving for the lawn's area directly instead of solving the reserved section and subtracting it from the total area of the whole place.
First, cut the lawn so that it becomes two shapes: a rectangle, and a triangle. Solve for both areas.
A(r) = lw
A(r) = (14)(16)
A(r) = 224 square feet
A(t) = bh/2
A(t) = (8)(14) / 2
A(t) = 112 / 2
A(t) = 56 square feet
Add the two areas:
A(r) + A(t) = Area of lawn
224 square feet + 56 square feet = 280 square feet.
The area of the lawn, therefores, is 280 ft^2.
I got 28
There is not parenthesis around the five meaning -5 squared would equal positive 25
